小编Joh*_*uan的帖子

MySQL - 无法使用SET变量创建视图

我试图用SET @rank = 0;内部创建一个视图,但它给了我错误.尝试过不同的东西,但它没有用.谁能指点我正确的方向?

CREATE VIEW S1_Bottom_Performer_AHT as (
SET @rank=0
SELECT @rank := @rank+1 AS '#',
                ei.SM,
                ei.TM,
                es.Month_Date,
                ei.emp_id,
                ei.DNAME,
                ei.STATUS,
                ei.SHIFT,
                ei.SKILL,
                ei.HIRE_DATE,
                ifnull(TIMESTAMPDIFF(MONTH, ei.HIRE_DATE, now()), '-') AS Tenure,
                ifnull(es.Call_Handled, '-') AS Call_Handled,
                ifnull(es.AHT, '-') AS AHT
FROM mtl_extended_info ei
LEFT OUTER JOIN
  ( SELECT es.Employee_ID,
           es.Month_Date,
           sum(es.Calls_Handled_Ct) AS Call_Handled,
           round((sum(es.I_Talk_Time_Sec) + sum(es.Hold_Time_Sec) + sum(es.I_Work_Time_Sec) + sum(es.I_AUX_Out_Time_Sec)) / sum(es.Calls_Handled_Ct)) AS AHT
   FROM cdl_agent_call_voume_gen es
   WHERE es.Month_Date = '2013-09-01'
   GROUP BY es.Employee_ID,
            es.Month_Date ) es ON …
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mysql sql

6
推荐指数
2
解决办法
2万
查看次数

使用jQuery UI datepicker选择日历更改URL

我正在使用jQuery UI选择器,我想知道当有人选择日期时它是否可能,它会自动将它们重定向到URL,如下所示:

index.php?date=2013-10-15

这是我正在使用的插件.

<script>
    $(function() {
        $( "#datepicker" ).datepicker();
    });
</script>
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Date: <input type="text" id="datepicker" />

jquery jquery-ui jquery-ui-datepicker

4
推荐指数
1
解决办法
8196
查看次数

jQuery - Bootstrap Datepicker onChange问​​题

我在选择日期时尝试更改链接,但每当我选择日期时,我都会得到 ?day=以下代码:

标记:

<i class="icon-calendar"></i>

它只在我使用输入时有效 <input type="text" class="datepicker">

使用Javascript:

        $(document).ready(function(){
            $(".datepicker").datepicker({
                format: "yyyy-mm-dd",
                endDate: "-2d"
            })

            .on('changeDate', function(ev){
                var dateData = $('.datepicker').val();
                window.location.href = "?day=" + dateData ;
            });
        });
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预期成绩: ?day=2013-11-01

谢谢

javascript jquery twitter-bootstrap

4
推荐指数
1
解决办法
2万
查看次数

Bootstrap - 将远程Google图表加载到模态中

我尝试将Google图表加载到模式中,但没有显示任何内容.我试过jsapi在index.html文件中加载仍然没有运气.还试图drawChart();在索引页面中调用该函数.仍然没有运气.

这是我的模拟

的index.html

<a data-toggle="modal" href="remote/modal.html" data-target=".modal" class="btn btn-sm btn-danger">Click Me!</a>

<div class="modal fade" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
    <div class="modal-dialog modal-lg">
        <div class="modal-content">
        </div>
    </div>
</div>
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modal.html

<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
    google.load("visualization", "1", {packages:["corechart"]});
    google.setOnLoadCallback(drawChart);
    function drawChart() {
        var data = new google.visualization.DataTable();
        data.addColumn('string', 'Month');
        data.addColumn('number', 'KPI 1');
        data.addColumn('number', 'KPI 1 Target');
        data.addColumn({type:'boolean',role:'certainty'});
        data.addColumn('number', 'KPI 2');
        data.addColumn('number', 'KPI 2 Target');
        data.addColumn({type:'boolean',role:'certainty'});
        data.addColumn('number', 'KPI 3 WR');
        data.addColumn('number', 'KPI 3 WR Target');
        data.addColumn({type:'boolean',role:'certainty'});
        data.addColumn('number', 'KPI 4 CA'); …
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jquery google-visualization twitter-bootstrap-3

2
推荐指数
1
解决办法
2897
查看次数

PHP - POST到Class无法正常工作

我有一个表格,我想发布到一个类,但无论何时,我点击提交,控制台返回一个GET而不是POST所有我的字段名称和URL在这样的URLhttp://rogerstracker.com/2/priority.php?yourName=&functionalArea=&publicationWeek=&otherCommunication=&LifeCycles%5B%5D=&priorityTitle=&IQLink=&IQliveDate=&nameOfKMSpecialist=&consideredPriority=&Content=&priorityRequest=Priority+Request&emp_id=&postPriorityRequest=Submit

这是我的课

class Post_Form
{

    private $db_connection              = null;
    private $lang                       = array();
    public  $errors                     = array();
    public  $messages                   = array();

    public function __construct()
    {
        $this->lang = & $GLOBALS['_language'];

        // if a POST request exist, call the insertNewPriorityRequest()

        if (isset($_POST["postPriorityRequest"])) {
            $this->insertNewPriorityRequest(currentDateTime(), $_POST["priorityRequest"], $_POST["yourName"], $_POST["emp_id"], $_POST["functionalArea"], $_POST["publicationWeek"], $_POST["otherCommunication"], $_POST["allAudiences"], $_POST["LifeCycles[]"], $_POST["priorityTitle"], $_POST["IQLink"], $_POST["IQliveDate"], $_POST["nameOfKMSpecialist"], $_POST["consideredPriority"], $_POST["Content"]);
        }
    }

    // Checks if database connection
    private function databaseConnection()
    {
        // connection already opened
        if ($this->db_connection != null) …
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php

-1
推荐指数
1
解决办法
64
查看次数