小编Pav*_*vel的帖子

如何使用纯令牌(令牌作为字符串)从控制器 $jwtManager->decode($jwt) 解析 jwt 令牌

所以我正在使用 Lexik JWT 身份验证包(Symfony 2.6)并使用以下代码成功创建用户和令牌:

$userRegistration = new UserRegistration();
$userRegistration->setPassword($request->request->get('password'));
$userRegistration->setEmail($request->request->filter('email'));
$userRegistration->setName($request->request->filter('name'));

$token = $this->jwtManager->create($RegisteredUser);
return $this->responseProvider->ok((object) [
    'userId' => $RegisteredUser->getId(),
    'token' => $token
]);
Run Code Online (Sandbox Code Playgroud)

回复 :

"data": {
    "userId": 24,
    "token": "eyJhbGciOiJSUzI1NiJ9.eyJyb2xlcyI6WyJST0xFX1VTRVIiXSwidXNlcm5hbWUiOiJqYWdhZHVAaHViaWktbmV0d29yay5jb20iLCJleHAiOjE1MzYxNTI0MDAsImlhdCI6MTUzNTU0NzYwMH0.B7gnfGdW1ijAIlo9xUI0DwkGaajQAQPBkRx4ChILXRNtpLdwgEl_9gvWdiidFbSXJseS8jslOfuAFUIWATmbNBoWVa3nc8SxkIrKI29xZuN6hB7R-63RH2BKsAVPsEjgTIJoqkkCrfrSum-_d3LEf36jcXqZb8M-GRKI477IwSDDwG_7YK5v0mu8N4TATXhN0tZGNYxp8Y27EI-g0Gmj9BIiobxnqVVoBWHN5J8d-UCrXRq94ifhEiQBxkG9r_eacMscB80n1VsiN2ouKH2kX-HRxRJmcgmydxvR7RcEW-P6koTxkaZJGO6mv7auSudTFlDENpwD4OD7gtn_wMUDS_OuN8WT7rZp8lwKY9f8J9fiGyq5J-8C_HmyjW-h8WhuJmTUaKhCZ-eLgDm4Vs2IQGYkHJEDFumnIZ607MAa1CW1ChAvurqvUqJ3G4TTN4wYqAHpSKz4y8SAMLjO91cedBPH6K5i9lh5htF-mW_htem7e5ornicU_djSccgHbxfXHQYTHCnqLp7-ONfl_p4nmhIEK0wcF0gkBXbIitzeTjy7C_uf_FV1sLPE5cY3PUP42DmHrG4PuXHLv_L1EjErkrpna7pChKA_TPeiZjqMcQoE70sZw8rr8KnRF2hpABdU_M2ZXOt_vF5-T8mLmKqs0LHxE089vVC3xsAh0mUr4FE"
} 
Run Code Online (Sandbox Code Playgroud)

当我尝试使用jwtManager->decode方法解码其他控制器中的当前令牌时,问题开始了:

$jwt = "eyJhbGciOiJSUzI1NiJ9.eyJyb2xlcyI6WyJST0xFX1VTRVIiXSwidXNlcm5hbWUiOiJqYWdhZHVAaHViaWktbmV0d29yay5jb20iLCJleHAiOjE1MzYxNTI0MDAsImlhdCI6MTUzNTU0NzYwMH0.B7gnfGdW1ijAIlo9xUI0DwkGaajQAQPBkRx4ChILXRNtpLdwgEl_9gvWdiidFbSXJseS8jslOfuAFUIWATmbNBoWVa3nc8SxkIrKI29xZuN6hB7R-63RH2BKsAVPsEjgTIJoqkkCrfrSum-_d3LEf36jcXqZb8M-GRKI477IwSDDwG_7YK5v0mu8N4TATXhN0tZGNYxp8Y27EI-g0Gmj9BIiobxnqVVoBWHN5J8d-UCrXRq94ifhEiQBxkG9r_eacMscB80n1VsiN2ouKH2kX-HRxRJmcgmydxvR7RcEW-P6koTxkaZJGO6mv7auSudTFlDENpwD4OD7gtn_wMUDS_OuN8WT7rZp8lwKY9f8J9fiGyq5J-8C_HmyjW-h8WhuJmTUaKhCZ-eLgDm4Vs2IQGYkHJEDFumnIZ607MAa1CW1ChAvurqvUqJ3G4TTN4wYqAHpSKz4y8SAMLjO91cedBPH6K5i9lh5htF-mW_htem7e5ornicU_djSccgHbxfXHQYTHCnqLp7-ONfl_p4nmhIEK0wcF0gkBXbIitzeTjy7C_uf_FV1sLPE5cY3PUP42DmHrG4PuXHLv_L1EjErkrpna7pChKA_TPeiZjqMcQoE70sZw8rr8KnRF2hpABdU_M2ZXOt_vF5-T8mLmKqs0LHxE089vVC3xsAh0mUr4FE";
$test = $this->jwtManager->decode($jwt);
Run Code Online (Sandbox Code Playgroud)

但是JWTManager::decode()必须实现接口Symfony\Component\Security\Core\Authentication\Token\TokenInterface而不是期望给出字符串。

我的目标只是从这个令牌中获取 userId,但找不到如何解码令牌的任何信息。有谁知道如何简单地解码令牌?

php decode symfony jwt lexikjwtauthbundle

4
推荐指数
2
解决办法
9297
查看次数

如何使用javascript计算字符串更改的数量

我试图用javascript计算一个字段(一个字符串)的更改次数.例如,在name = MARTIN:MARTI => 1更改MARTINE => 1更改MATRIN => 2更改MARBOM => 3更改

javascript levenshtein-distance

0
推荐指数
1
解决办法
108
查看次数