这段代码不应该适用于 R 中的重复数字检测吗？
> grep(pattern = "\\d{2}", x = 1223)
[1] 1
> grep(pattern = "\\d{3}", x = 1223)
[1] 1
如果有 988，我们应该得到 true；如果有 123，我们应该得到 false。
听起来好像不是。
> grep(pattern = "\\d{2}", x = "1223")
[1] 1
> grep(pattern = "\\d{2}", x = "13")
[1] 1
我想给一个名为State的类的每个子项赋值,而我有一个状态数组最初都为null,我在这里接收空指针引用:
//finding all the neighbor states of a given configuration
public State[] neighborStates(String config, int modeFlag){
State[] neighborStates=new State[7];
int i=0;
for (Operation o : Operation.values()){
neighborStates[i].config=move(config,o.name().charAt(0));
neighborStates[i].realCost++;
neighborStates[i].opSequence+=o.name();
neighborStates[i].heuristicCost=getHeuristicCost(neighborStates[i].config, modeFlag);
i++;
}
return neighborStates;
}
我将代码更改为此但我还是获得了NPE:
public State[] neighborStates(String config, int modeFlag){
State[] neighborStates=new State[8];
int i=0;
for (Operation o : Operation.values()){
neighborStates[i] = new State(move(config,o.name().charAt(0)),neighborStates[i].realCost++,
getHeuristicCost(neighborStates[i].config, modeFlag), neighborStates[i].opSequence+=o.name());
//neighborStates[i].config=move(config,o.name().charAt(0));
//neighborStates[i].realCost++;
//neighborStates[i].opSequence+=o.name();
//neighborStates[i].heuristicCost=getHeuristicCost(neighborStates[i].config, modeFlag);
i++;
}
类State定义为:
public class State {
public State(String config, int realCost, int heuristicCost, String …我有一个csv文件,我只想提取句子的时间戳,其中包含该句子中的水果名称.我怎么能在R中这样做(或者如果有更快的方法,那是什么？)
rosbagTimestamp,data
1438293900729698553,robot is in motion toward [strawberry]
1438293900730571638,Found a plan for avocado in 1.36400008202 seconds
1438293900731434815,current probability is greater than EXECUTION_THRESHOLD
1438293900731554567,ready to execute am original plan of len = 33
1438293900731586463,len of sub plan 1 = 24
1438293900731633713,len of sub plan 2 = 9
1438293900732910799,put in an execution request; now updating the dict
1438293900732949576,current_prediciton_item = avocado
1438293900733070339,current_item_probability = 0.880086981207
1438293901677787230,current probability is greater than PLANNING_THRESHOLD
1438293901681590725,robot is in motion toward [avocado]
1438293902689233770,we have received verbal request …当三角形为等腰三角形时，如何总结这段代码？
1 #!/bin/bash
2
3 read x y z
4
5 if [[ x -eq z ]] && [[ x -eq y ]] && [[ y -eq z ]]; then
6 echo EQUILATERAL
7 elif [[ x -eq z ]] && [[ x -eq y ]]
8 then
9 echo ISOSCELES
10 elif [[ y -eq z ]] && [[ y -eq x ]]
11 then
12 echo ISOSCELES
13 elif [[ z -eq x ]] && [[ z -eq …我收到以下错误:
ViewDoesNotExist at /
'<HttpResponse status_code=200, "text/html; charset=utf-8">' is not a callable or a dot-notation path
Request Method: GET
Request URL: http://0.0.0.0:8000/
Django Version: 1.9.7
Exception Type: ViewDoesNotExist
Exception Value:
'<HttpResponse status_code=200, "text/html; charset=utf-8">' is not a callable or a dot-notation path
Exception Location: /Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/django/core/urlresolvers.py in get_callable, line 102
Python Executable: /Library/Frameworks/Python.framework/Versions/3.4/bin/python3
Python Version: 3.4.1
Python Path:
['/Users/mona/interviews/django/learning_site',
'/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/beautifulsoup4-4.3.2-py3.4.egg',
'/Library/Frameworks/Python.framework/Versions/3.4/lib/python34.zip',
'/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4',
'/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/plat-darwin',
'/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/lib-dynload',
'/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages']
Server time: Mon, 20 Jun 2016 13:18:23 +0000
运行此命令时:
$ python3 manage.py runserver 0.0.0.0:8000
Performing system …如何修复我的代码,以便找到有效的(){} []？现在,它只返回true.
public static boolean isValid(String s){
HashMap<Character, Character> specialChar= new HashMap<>();
specialChar.put('{', '}');
specialChar.put('[',']');
specialChar.put('(',')');
Stack<Character> stk = new Stack<>();
for (int i=0; i<s.length(); i++){
if (specialChar.keySet().contains(s.charAt(i))){
stk.push(s.charAt(i));
}
else if (specialChar.values().contains(s.charAt(i))){
if (!stk.empty()) {
stk.pop();
}
}
}
return stk.isEmpty();
}
System.out.println(isValid("{}{lll}]"));
检测文本(特别是Instagram评论)是非英语的最准确方法是什么？我很乐意使用任何高级语言,例如Python,PHP等.
$ sudo pip2 install guess_language
>>> from guess_language import guessLanguage
>>> guessLanguage('la vita e bella')
'UNKNOWN'
>>> guessLanguage('today is a good day')
'UNKNOWN'
>>> guessLanguage('????????????????(???)')
'ja'
与
$ sudo apt-get install php5.6-mbstring
if(strlen($comment->text) == mb_strlen($comment->text, 'utf-8')) {
echo '- '.$comment->text."\n";
}
我得到许多不是英文的英文字符:例子:
- Khoda be khanevadehashon sabr bede tahamol konan
- Akhey...
- Eshghi
- K
- :-)
- Ey khodaa
- ...
- @samaneaghazamani1990 vaaaaay khoda chejoori payam dadan?
- :(
- Elahiiiii
- May Allah please with …