最近我设计了元类型和允许编译时类型连接的可能操作:
#include <tuple>
template<template<typename...> typename T>
struct MetaTypeTag
{};
/*variable template helper*/
template<template<typename...> typename T>
constexpr MetaTypeTag<T> meta_type_tag = {};
template<typename T>
struct TypeTag
{};
/*comparison*/
template<typename T>
constexpr bool operator==(TypeTag<T>, TypeTag<T>) { return true; }
template<typename T, typename U>
constexpr bool operator==(TypeTag<T>, TypeTag<U>) { return false; }
/*variable template helper*/
template<typename T>
constexpr TypeTag<T> type_tag = {};
template<template<typename...> typename T, typename... Ts>
constexpr TypeTag<T<Ts...>> combine(MetaTypeTag<T>, TypeTag<Ts>...)
{
return {};
}
int main()
{
constexpr auto combined_tag = combine(meta_type_tag<std::tuple>, type_tag<int>, …
Run Code Online (Sandbox Code Playgroud) c++ metaprogramming template-meta-programming constexpr c++11