import re
from decimal import *
import numpy
from scipy.signal import cspline1d, cspline1d_eval
import scipy.interpolate
import scipy
import math
import numpy
from scipy import interpolate
Y1 =[0.48960000000000004, 0.52736099999999997, 0.56413900000000006, 0.60200199999999993, 0.64071400000000001, 0.67668399999999995, 0.71315899999999999, 0.75050499999999998, 0.61494199999999999, 0.66246900000000009]
X1 =[0.024, 0.026000000000000002, 0.028000000000000004, 0.029999999999999999, 0.032000000000000001, 0.034000000000000002, 0.035999999999999997, 0.038000000000000006, 0.029999999999999999, 0.032500000000000001]
rep = scipy.interpolate.splrep(X1,Y1)
在上面的代码我得到和错误
Traceback (most recent call last):
File "/home/vibhor/Desktop/timing_tool/timing/interpolation_cap.py", line 64, in <module>
rep = scipy.interpolate.splrep(X1,Y1)
File "/usr/lib/python2.6/site-packages/scipy/interpolate/fitpack.py", line 418, in splrep
raise _iermess[ier][1],_iermess[ier][0]
ValueError: Error on input data
不知道发生了什么
我在 x 和 y 轴上有数据，输出在 z 上
例如
y = 10
x = [1,2,3,4,5,6]
z = [2.3,3.4,5.6,7.8,9.6,11.2]
y = 20
x = [1,2,3,4,5,6]
z = [4.3,5.4,7.6,9.8,11.6,13.2]
y = 30
x = [1,2,3,4,5,6]
z = [6.3,7.4,8.6,10.8,13.6,15.2]
当 y = 15 x = 3.5 时如何找到 z 的值
我试图使用 scipy 但我对它很陌生
非常感谢您的帮助
维布尔