小编rah*_*hul的帖子

可能是问题之前,但我发现非常奇怪的错误.当我mvn --version从bin 运行命令时,它会给出版本和其他信息.但是,当我在bin外面运行时,它会给出异常.结果都提到了下面

C:\Program Files\apache-maven-3.0.5-bin\apache-maven-3.0.5\bin>mvn --version
Apache Maven 3.0.5 (r01de14724cdef164cd33c7c8c2fe155faf9602da; 2013-02-19 19:21:
28+0530)
Maven home: C:\Program Files\apache-maven-3.0.5-bin\apache-maven-3.0.5
Java version: 1.7.0_25, vendor: Oracle Corporation
Java home: C:\Program Files\Java\jdk1.7.0_25\jre
Default locale: en_US, platform encoding: Cp1252
OS name: "windows 7", version: "6.1", arch: "amd64", family: "windows"

C:\Program Files\apache-maven-3.0.5-bin\apache-maven-3.0.5>mvn --version
'mvn' is not recognized as an internal or external command,
operable program or batch file.

另外我将JAVA_HOME设置在用户变量和M2_HOME中,M2在系统环境变量输出中

C:\Users\SAHILBHALLA>echo %JAVA_HOME%
C:\Program Files\Java\jdk1.7.0_25

C:\Users\SAHILBHALLA>echo %M2%
C:\Program Files\apache-maven-3.0.5-bin\apache-maven-3.0.5\bin

C:\Users\SAHILBHALLA>echo %M2_HOME%
C:\Program Files\apache-maven-3.0.5-bin\apache-maven-3.0.5

告诉我我错在哪里.我应该从中恢复什么？

我是 Spring 新手，尝试创建应用程序，以便我可以了解它的工作原理。但是当我写代码时Eclipse IDE gives

无法解析 javax.servlet.http.HttpServletResponse 类型。它是从所需的 .class 文件间接引用的

这是我的课

package testPackage;  
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.SimpleFormController;
import domain.serviceLayer.UserService;
import domain.userDetails.User;

@SuppressWarnings("deprecation")
public class UserLoginFormController extends SimpleFormController  {
    private UserService userService;

    public UserLoginFormController() {
        setCommandClass(User.class);
        setCommandName("user");
    }
    public void setUserService(UserService userService) {
        this.userService = userService;
    }

    @Override
    public ModelAndView onSubmit(Object command) throws Exception {
        // TODO Auto-generated method stub

        User user = (User) command;
        userService.add(user);
        ModelAndView modelAndView = new ModelAndView("success", "user", user);
        return modelAndView;
    } 
}

和 pom.xml

<project …

<div class="cdlButton" style="width:40px; float: left;">  // want this div element
     <div style="">
         <a id="changestatus" class="" onclick="changeWorkflowStatus()" href="#">
             <img id="" width="32px" height="32px" title="disable" alt="disable"  src="images/disable.png">
        </a>
    </div>
</div>

我希望div在jquery的帮助下现在我正在这样做

 $("#changestatus ").parent().parent().addClass('disablecdlButton');

有没有其他方法来获得顶级div元素