因此,我试图结合进行查询和做到这一点,我需要弄清楚这是怎么回事。我对SQL Server还是比较陌生,因此我不得不深入研究一些复杂的qrys,有时我会陷入类似这样的简单问题。我的问题是使用了Sum(1)函数,但我不确定如何使用。这意味着我相信它正在计算重复项,但我无法根据它所提供的信息来判断。
这是查询
SELECT
qryReinsuranceDPA1.POLICY_NO,
qryReinsuranceDPA1.PHASE_CODE,
qryReinsuranceDPA1.SUB_PHASE_CODE,
qryReinsuranceDPA1.ProdType,
TotalDPA = Sum(case when [SumOfNetDefExtraAdj] Is Null then [SumOfNetDefPremiumAdj] else [SumOfNetDefPremiumAdj] + SumOfNetDefExtraAdj end),
Sum(1) AS Expr1
FROM qryPolicyListforNYDefPRemAsset_Re RIGHT JOIN qryReinsuranceDPA1
ON
qryReinsuranceDPA1.POLICY_NO = qryPolicyListforNYDefPRemAsset_Re.POLICY_NO AND
qryReinsuranceDPA1.PHASE_CODE= qryPolicyListforNYDefPRemAsset_Re.PHASE_CODE AND
qryReinsuranceDPA1.SUB_PHASE_CODE = qryPolicyListforNYDefPRemAsset_Re.SUB_PHASE_CODE
GROUP BY qryReinsuranceDPA1.POLICY_NO,
qryReinsuranceDPA1.PHASE_CODE,
qryReinsuranceDPA1.SUB_PHASE_CODE,
qryReinsuranceDPA1.ProdType
--HAVING (((Sum(1))<>1))
GO
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这只是它产生的一小部分样本(实际结果约为77,000)
POLICY_NO PHASE_CODE SUB_PHASE_CODE ProdType TotalDPA Expr1
228433800 0 1 TERM 282.324223 1
228439200 0 1 PERM 53.17048634 1
228439200 6 1 PERM 10.3805065 1
228441500 0 1 PERM 526.6883742 …Run Code Online (Sandbox Code Playgroud)