我想运行一个find命令,找到一个特定的文件列表,然后遍历该文件列表来运行一些操作.我还想查找该列表中所有文件的总大小.
我想把文件列表放在第一位,然后做其他操作.有没有一种简单的方法可以报告列表中所有文件的总大小?
本质上,我试图在下面的代码片段中找到'total_size'变量的单行代码:
#!/bin/bash
loc_to_look='/foo/bar/location'
file_list=$(find $loc_to_look -type f -name "*.dat" -size +100M)
total_size=???
echo 'total size of all files is: '$total_size
for file in $file_list; do
# do a bunch of operations
done
Run Code Online (Sandbox Code Playgroud) 我有以下示例代码:
import numpy as np
import matplotlib.pyplot as plt
import random
data_theta = range(10,171,10)
data_theta_rad = []
for i in data_theta:
data_theta_rad.append(float(i)*np.pi/180.0)
data_r = random.sample(range(70, 90), 17)
print data_theta
print data_r
ax = plt.subplot(111, polar=True)
ax.plot(data_theta_rad, data_r, color='r', linewidth=3)
ax.set_rmax(95)
# ax.set_rmin(70.0)
ax.grid(True)
ax.set_title("Example", va='bottom')
plt.show()
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...产生这样的东西:

...但我想将theta = 0设置为'West'.所以类似于:

任何想法如何用matplotlib做这个(我在powerpoint中制作了下面的图片)?
我有一个示例脚本来制作径向等高线图:
import os
import math
import numpy as np
import matplotlib.pyplot as plt
import mpl_toolkits.axisartist.floating_axes as floating_axes
from matplotlib.projections import PolarAxes
from mpl_toolkits.axisartist.grid_finder import FixedLocator, MaxNLocator, DictFormatter
import random
# ------------------------------------ #
def setup_arc_radial_axes(fig, rect, angle_ticks, radius_ticks, min_rad, max_rad):
tr = PolarAxes.PolarTransform()
pi = np.pi
grid_locator1 = FixedLocator([v for v, s in angle_ticks])
tick_formatter1 = DictFormatter(dict(angle_ticks))
grid_locator2 = FixedLocator([a for a, b in radius_ticks])
tick_formatter2 = DictFormatter(dict(radius_ticks))
grid_helper = floating_axes.GridHelperCurveLinear(tr,
extremes=((370.0*(pi/180.0)), (170.0*(pi/180.0)), max_rad, min_rad),
grid_locator1=grid_locator1,
grid_locator2=grid_locator2,
tick_formatter1=tick_formatter1,
tick_formatter2=tick_formatter2,
)
ax1 …Run Code Online (Sandbox Code Playgroud) 我有一个应用程序,需要一个以准随机方式填充'n'点的磁盘.我希望这些点有点随机,但在磁盘上仍然具有或多或少的常规密度.
我当前的方法是放置一个点,检查它是否在磁盘内,然后检查它是否也远离已经保留的所有其他点.我的代码如下:
import os
import random
import math
# ------------------------------------------------ #
# geometric constants
center_x = -1188.2
center_y = -576.9
center_z = -3638.3
disk_distance = 2.0*5465.6
disk_diam = 5465.6
# ------------------------------------------------ #
pts_per_disk = 256
closeness_criteria = 200.0
min_closeness_criteria = disk_diam/closeness_criteria
disk_center = [(center_x-disk_distance),center_y,center_z]
pts_in_disk = []
while len(pts_in_disk) < (pts_per_disk):
potential_pt_x = disk_center[0]
potential_pt_dy = random.uniform(-disk_diam/2.0, disk_diam/2.0)
potential_pt_y = disk_center[1]+potential_pt_dy
potential_pt_dz = random.uniform(-disk_diam/2.0, disk_diam/2.0)
potential_pt_z = disk_center[2]+potential_pt_dz
potential_pt_rad = math.sqrt((potential_pt_dy)**2+(potential_pt_dz)**2)
if potential_pt_rad < (disk_diam/2.0):
far_enough_away = True
for pt …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用 gnuplot 5.0 来绘制一个没有边距、边框或轴的二维数据数组......只是一个表示某些数据的二维图像(.png 或 .jpg)。我希望每个数组元素都对应于图像中的一个像素,没有缩放/插值等,并且边缘没有额外的白色像素。
到目前为止,当我尝试将边距设置为 0 甚至使用pixels标志时,我仍然在图像的右侧和顶部边框上留下一行白色像素。
我怎样才能得到一个图像文件,其中包含数据数组的逐像素表示,而没有额外的东西?
gnuplot 脚本:
#!/usr/bin/gnuplot --persist
set terminal png size 400, 200
set size ratio -1
set lmargin at screen 0
set rmargin at screen 1
set tmargin at screen 0
set bmargin at screen 1
unset colorbox
unset tics
unset xtics
unset ytics
unset border
unset key
set output "pic.png"
plot "T.dat" binary array=400x200 format="%f" with image pixels notitle
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来自 Fortran 90 的示例数据:
program …Run Code Online (Sandbox Code Playgroud) 我想用它们的绝对值为Excel 2010中的值表着色.基本上,如果我有桌子:

......细胞被细胞的原始值着色.我想做的是按单元格的绝对值进行着色,所以使用此表格的单元格着色:

...但是使用第一个表的值(实际值).关于如何做到这一点的任何想法?通过GUI或VBA?
我有以下VBA代码来创建一个新的PowerPoint幻灯片:
longSlideCount = ActivePresentation.Slides.Count
With ActivePresentation.Slides
Set slideObject = .Add(longSlideCount + 1, ppLayoutTitle)
End With
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...插入'ppLayoutTitle'类型的新幻灯片,但我想知道是否可以在'幻灯片母版视图'中创建自定义布局,然后将该特定幻灯片模板插入到演示文稿中?
提前致谢!!!
我正在Visual Basic for PowerPoint 2010中编写一个宏.我想初始化一个非常大的字符串列表,如:
big_ol_array = Array( _
"string1", _
"string2", _
"string3", _
"string4" , _
.....
"string9999" _
)
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...但是我在编辑器中收到"Too many lines continuations"错误.当我尝试初始化没有换行符的大数组时,VB编辑器无法处理这么长的行(1000+)字符.
有谁知道在VB中初始化一个庞大的字符串列表的好方法?
提前致谢!
我给出了三个要点的位置:
p1 = [1.0, 1.0, 1.0]
p2 = [1.0, 2.0, 1.0]
p3 = [1.0, 1.0, 2.0]
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及其转换后的对应对象:
p1_prime = [2.414213562373094, 5.732050807568877, 0.7320508075688767]
p2_prime = [2.7677669529663684, 6.665063509461097, 0.6650635094610956]
p3_prime = [2.7677669529663675, 5.665063509461096, 1.6650635094610962]
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仿射变换矩阵的形式为
trans_mat = np.array([[…, …, …, …],
[…, …, …, …],
[…, …, …, …],
[…, …, …, …]])
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这样与
import numpy as np
def transform_pt(point, trans_mat):
a = np.array([point[0], point[1], point[2], 1])
ap = np.dot(a, trans_mat)[:3]
return [ap[0], ap[1], ap[2]]
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你会得到:
transform_pt(p1, trans_mat) == p1_prime
transform_pt(p2, trans_mat) …Run Code Online (Sandbox Code Playgroud) python linear-algebra coordinate-systems homogenous-transformation coordinate-transformation
我想知道如何在matplotlib中显式设置colorbar对象的格式
以下是绘制脚本的示例:
from matplotlib import pyplot
from matplotlib.ticker import MultipleLocator, FormatStrFormatter
from matplotlib.colors import BoundaryNorm
from matplotlib.ticker import MaxNLocator
from pylab import *
import numpy as np
import random
# ----------
plot_aspect = 1.2
plot_height = 10.0
plot_width = int(plot_height*plot_aspect)
# ----------
pyplot.figure(figsize=(plot_width, plot_height), dpi=100)
pyplot.subplots_adjust(left=0.10, right=1.00, top=0.90, bottom=0.06, hspace=0.30)
subplot1 = pyplot.subplot(111)
# ----------
cbar_max = 40.0
cbar_min = 20.0
cbar_step = 1.0
cbar_num_colors = 200
cbar_num_format = "%d"
# ----------
# make random dataset
dx, dy = 5.0, …Run Code Online (Sandbox Code Playgroud)