小编Com*_*low的帖子

我有以下场景:

Load Page A
Check if Element_A exists in Page A
Click Button_A
On Clicking Button_A, Page B is loaded
Check if Element_B exists in Page B and Click Button_B
and so on...

我写了这样的代码:

import unittest
from selenium import webdriver
from selenium.webdriver.common.keys import Keys

class MyWebsiteTest(unittest.TestCase):

    def setUp(self):
        self.driver = webdriver.Firefox()

    def test_element_a_in_page_a(self):
        driver = self.driver
        driver.get(PAGE_A)
        element = driver.get_element_by_id("element_a")
        self.assertIsNotNone(element,"Oops.")

    def load_page_b_if_previous_function_is_true(self):
        #WHAT DO I DO HERE?
        #I Need to run this function given test_element_a_in_page_a succeeds.

    def tearDown(self):
        self.driver.close() …

我有一本csv通过大熊猫阅读的书read_csv,

data = pandas.read_csv(file)

现在一小部分是这样的,

data['interest']:

one.a
two.a
three.a
four.b

等等...

我想创建一个新的pandas系列,比方说,

data['i']它只包含第一部分data['interest'],即

one
two
three
four

现在我可以遍历整个事情split,但是我可以用地图做吗？

像 - data['i'] = map(split_and_get_first_part, data['interest'])？

我有一个像这样的json:

{
"a": {
    "x": {
        "y": {
            "a": {}, 
            "z": {}, 
            "b": {}
        }
    }, 
    "c": {}, 
    "b": {
        "c": {
            "d": {}
        }
    }, 
    "d": {}, 
     ...
    }
}

有没有快速的方法将其转换为flare.json格式？

像这样:

{
"name":"a",
"children":[
      {
      "name":"x",
      "children":
            {
              "name":"y",
              "children":[{"name":"a", "size":0},{"name":"z","size":0},{"name":"b","size":0}]

...
}

谢谢.

我的表是这样的:

| A | B | ...
---------
| 1 | a | ...
---------
| 2 |   |
---------
| 3 |   |
---------
| 4 | b |
---------

我希望这是我的输出:

| A | B | ...
---------
| a |   | ...
---------
| 2 |   |
---------
| 3 |   |
---------
| b |   |
---------

所以我循环列B,只要有值,B那么我应该替换相应的值A

到目前为止,我尝试过这样的:

Sub LoopRange()

   Dim rCell As Range
   Dim rRng As Range

   Set rRng1 = …

所以我有一个像这样的laaaaaaaarge文件:

Item|Cost1|Cost2
Pizza|50|25
Sugar|100|100
Spices|100|200
Pizza|100|25
Sugar|200|100
Pizza|50|100

我想为特定项添加所有Cost1s和Cost2s并生成合并输出.

我写了一个python代码来做到这一点,

item_dict = {}
for line in file:
    fields = line.split('|')
    item = fields[0]
    cost1 = fields[1]
    cost2 = fields[2]
    if item_dict.has_key(item):
        item_dict[item][0] += int(cost1)
        item_dict[item][1] += int(cost2)
    else:
        item_dict[item] = [int(cost1),int(cost2)]

for key, val in item_dict.items():
    print key,"|".join(val)

无论如何,在awk或使用任何其他魔法中非常有效和快速地执行此操作？

或者我可以让我的python更优雅,更快？

预期产出

Pizza|200|150
Sugar|300|200
Spices|100|200

我有这样的代码:

count = 0

for line in lines:

    #do something with line
    #do something more with line
    #finish doing that thing with line

    count = count + 1
    if count % 10000 == 0:
        print count

这是在python中维护count变量的正确方法吗？我可以让它看起来更好吗？

我有这样的excel表:

A | B
-----
0 | 2
0 | 3
0 | 4
0 | 5
0 | 6
0 | 7
1 | 8
1 | 9
1 | 10
1 | 11
1 | 12
2 | 13
2 | 14

...

如何获取A中每个值最后一次出现的B的值？

输出是 -

C | D
0 | 7
1 | 12
2 | 14

有这么简单的方法吗？谢谢!

我有一个映射器。

for line in sys.stdin:
    #if line is from file1
    #process it based on some_arbitrary_logic
    #emit k,v

    #if line is from file2
    #process it based on another_arbitrary_logic
    #emit k, v

我需要通过 hadoop 流 API-input file1和另一个-input file2.

我如何实现这一目标？我怎么知道STDINhadoop流给我的哪一行属于哪个文件？

更新

File1

Fruit, Vendor, Cost

Oranges, FreshOrangesCompany, 50
Apples, FreshAppleCompany, 100

File2

Vendor, Location, NumberOfOffices

FreshAppleCompany, NewZealand, 45
FreshOrangeCompany, FijiIslands, 100

我需要做的是打印出他们卖橙子的办公室数量。

Oranges 100.

所以这两个文件都需要到INPUT映射器。

这是最蟒蛇的做法 -

ys = []
for x in xs:
    z = compute_something(x)
    #z is an object of some class
    ys.append(z.a_property_of_z)

return ys

或者我可以在一些聪明的列表理解中处理上述内容吗？或函数式编程？还是其他一些蟒蛇魔法？