我在django.template中有以下代码:
class Template(object):
def __init__(self, template_string, origin=None, name='<Unknown Template>'):
try:
template_string = smart_unicode(template_string)
except UnicodeDecodeError:
raise TemplateEncodingError("Templates can only be constructed from unicode or UTF-8 strings.")
if settings.TEMPLATE_DEBUG and origin is None:
origin = StringOrigin(template_string)
self.nodelist = compile_string(template_string, origin)
self.name = name
def __iter__(self):
for node in self.nodelist:
for subnode in node:
yield subnode
def render(self, context):
"Display stage -- can be called many times"
return self.nodelist.render(context)
Run Code Online (Sandbox Code Playgroud)
我困惑的部分如下.这种__iter__
方法有什么用?我找不到任何相应的next
方法.
def __iter__(self):
for node in self.nodelist:
for subnode …
Run Code Online (Sandbox Code Playgroud) 我只知道一种方式:
右键单击并单击"删除我"
我还可以在Google地图上删除标记吗?
这是我现在的代码:
GEvent.addListener(marker, 'mousedown', function(e) {
alert(e)
if (e.button == 2){
alert('sss')
map.removeOverlay(marker);
}
Run Code Online (Sandbox Code Playgroud)
当我右键单击时,它会发出警报(40.23141543543321,114.3214121421)
; 当我查看API时,我看到了这个:
mousedown(latlng:GLatLng)
Run Code Online (Sandbox Code Playgroud)
所以我认为这e
不是一个事件,而是'GLatLng'
如果我使用'singlerightclick',当我右键单击时没有任何反应.
这是我的完整代码:
<!DOCTYPE html PUBLIC "-//WAPFORUM//DTD XHTML Mobile 1.0//EN" "http://www.wapforum.org/DTD/xhtml-mobile10.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<meta name="viewport" content="width=device-width,minimum-scale=0.3,maximum-scale=5.0,user-scalable=yes">
</head>
<body onload="initialize()" onunload="GUnload()">
<style type="text/css">
*{
margin:0;
padding:0;
}
#head{
height:70px;
background:#a00;
}
#logo{
color:white;
font-weight:bold;
line-height:70px;
margin-left:100px;
}
#main{
position:relative;
margin-top:1px;
}
#left{
border:1px solid red;
height:700px;
margin-right:202px;
}
#top{
font-weight:bold;
line-height:70px;
margin-left:120px; …
Run Code Online (Sandbox Code Playgroud) from copy import*
a=[1,2,3,4]
c={'a':'aaa'}
print c
#{'a': 'aaa'}
b=deepcopy(a,c)
print b
print c
# print {'a': 'aaa', 10310992: 3, 10310980: 4, 10311016: 1, 11588784: [1, 2, 3, 4, [1, 2, 3, 4]], 11566456: [1, 2, 3, 4], 10311004: 2}
Run Code Online (Sandbox Code Playgroud)
为什么c打印出来
请尝试使用代码,而不是文字,因为我的英语不是很好,谢谢
在django.utils.tree.py中
def __deepcopy__(self, memodict):
"""
Utility method used by copy.deepcopy().
"""
obj = Node(connector=self.connector, negated=self.negated)
obj.__class__ = self.__class__
obj.children = deepcopy(self.children, memodict)
obj.subtree_parents = deepcopy(self.subtree_parents, memodict)
return obj
import copy
memo = {}
x1 = range(5)
x2=range(6,9)
x3=[2,3,4,11] …
Run Code Online (Sandbox Code Playgroud) 还有其他争论key
,例如:value
?
常规的dom元素如下:
document.getElementById('a')
要么
document.createElement('div')
但是jQuery以另一种格式返回元素,所以例如我想将返回的内容转换为与返回$('#a')
的内容相同的结果.document.getElementById('a')
这可能使用jQuery吗?
谢谢
使用Google Maps API v3:当鼠标悬停在特定区域时,如何更改鼠标光标?
这是我的中间件代码:
from django.conf import settings
from django.template import RequestContext
class BeforeFilter(object):
def process_request(self, request):
settings.my_var = 'Hello World'
request.ss = 'ssssssssss'
return None
def process_response(self, request, response):
return response
Run Code Online (Sandbox Code Playgroud)
这是settings.py:
TEMPLATE_CONTEXT_PROCESSORS = (
'django.core.context_processors.request',
)
MIDDLEWARE_CLASSES = (
...
'middleware.BeforeFilter',
)
Run Code Online (Sandbox Code Playgroud)
而且观点是:
#coding:utf-8
from django.conf import settings
from django.shortcuts import render_to_response
from django.http import HttpResponse
from django.template import RequestContext
def index(request):
context = RequestContext(request)
context['a'] = 'aaaa'
return render_to_response('a.html',context)
Run Code Online (Sandbox Code Playgroud)
HTML是:
{{a}}fffff{{ss}}
Run Code Online (Sandbox Code Playgroud)
但它没有显示{{ss}}:
aaaafffff
Run Code Online (Sandbox Code Playgroud)
那我怎么展示:
aaaafffffssssssss
Run Code Online (Sandbox Code Playgroud)
如何使用django中间件在所有django上下文中插入一些文本,
所以我不能每次都插入文本,
谢谢
这是我的代码:
print '??'.decode('gb2312').encode('utf-8')
Run Code Online (Sandbox Code Playgroud)
...它打印:
SyntaxError: Non-ASCII character '\xe5' in file D:\zjm_code\a.py on line 2, but no encoding declared; see http://www.python.org/peps/pep-0263.html for details
Run Code Online (Sandbox Code Playgroud)
我该如何打印'哈哈'?
更新: 当我使用以下代码时:
#!/usr/bin/python
# -*- coding: utf-8 -*-
print '??'
Run Code Online (Sandbox Code Playgroud)
...打印???
.这不是我想要的.
我的IDE是Ulipad,这是IDE的错误吗?
第二次更新:
此代码将正确打印字符:
#!/usr/bin/python
# -*- coding: utf-8 -*-
print u'??'.encode('gb2312')
Run Code Online (Sandbox Code Playgroud)
......当我用它时:
#!/usr/bin/python
# -*- coding: utf-8 -*-
a='??'
print a.encode('gb2312')
Traceback (most recent call last):
File "D:\zjm_code\a.py", line 5, in <module>
print a.encode('gb2312')
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe5 in position 0: …
Run Code Online (Sandbox Code Playgroud) python ×6
javascript ×3
google-maps ×2
cjk ×1
django ×1
iterator ×1
jquery ×1
key ×1
python-2.x ×1
python-3.x ×1
sorting ×1
sqlite ×1
templates ×1
yield ×1