SELECT id, content, date
FROM comment
WHERE post = ?
ORDER BY date DESC
LIMIT ?, ?
使用PDO(我正在使用具有Apache 2.2.21的MAMP 2.0.5,PHP高达5.3.6和MySQL 5.5.9)准备语句这不起作用,如果我更改查询
LIMIT 0, 10
有用.
我在MySQL的错误中看到这是以前版本中的一个错误,但我无法理解这是否仍有待修复.
如果这仍然是个问题,有办法以另一种方式选择一系列行吗？
码:
$comments = $db->prepare($query);
/* where $db is the PDO object */
$comments->execute(array($post, $min, $max));
index.html(Offerer)
var socket = io.connect('http://127.0.0.1:80'); //socket.io
socket.emit("player 1");
var iceServers = {
iceServers: [
{"url":"stun:turn1.xirsys.com"},
{"username":"myusername","url":"turn:turn1.xirsys.com:443?transport=udp","credential":"mycredential"},
{"username":"myusername","url":"turn:turn1.xirsys.com:443?transport=tcp","credential":"mycredential"}
]
};
var offererDataChannel, answererDataChannel;
var Offerer = {
createOffer: function () {
var peer = new PeerConnection(iceServers);
var dataChannelOptions = {
reliable: true,
ordered: false
};
offererDataChannel = peer.createDataChannel('channel', dataChannelOptions);
setChannelEvents(offererDataChannel);
peer.onicecandidate = function (event) {
if (event.candidate) {
socket.emit("candidate", event.candidate);
}
};
peer.createOffer(function (sdp) {
peer.setLocalDescription(sdp);
socket.emit("sdp", sdp);
}, function (err) { peer.close(); });
this.peer = peer;
return this; …我正在尝试创建一个程序,用于读取Mac OS X(当前版本10.9.5)上的UDP数据包的IP地址和端口(在本例中为localhost).
给我一些有用数据的唯一一个是tcpdump和nc(netcat),但它只工作了一次.这就是我所做的:
1°终端窗口
$ sudo tcpdump -i en0 -X -v 'udp port 60000'
tcpdump: listening on en0, link-type EN10MB (Ethernet), capture size 65535 bytes
* new packet with the string 'Hello' at the end *
2°终端窗口
$ nc -u 192.168.1.67 60000
Hello
$
我对这个论点没有太多的了解,所以最后的问题是:
如果我需要创建一个程序,需要读取给定端口号的任何UDP数据包并通过同一端口将UDP数据包发送到任何IP地址,那么最简单的方法是什么？我试图通过C使用libpcap,但没有成功.
"编写一个函数lv: cfg -> (blabel -> ide set),计算给定控制流图上的实时变量分析."
拥有cfg并blabel定义并ide set作为字符串列表,如何创建具有该签名的函数？
这是我的代码，仅适用于 Xcode（版本 4.5）：
\n\n#include <stdio.h>\n#include <mach/mach_init.h>\n#include <mach/mach_vm.h>\n#include <sys/types.h>\n#include <mach/mach.h>\n#include <sys/ptrace.h>\n#include <sys/wait.h>\n#include <Security/Authorization.h>\n\nint main(int argc, const char * argv[]) {\n\n char test[14] = "Hello World! "; //0x7fff5fbff82a\n\n char value[14] = "Hello Hacker!";\n\n char test1[14];\n\n pointer_t buf;\n uint32_t sz;\n\n task_t task;\n\n task_for_pid(current_task(), getpid(), &task);\n\n if (vm_write(current_task(), 0x7fff5fbff82a, (pointer_t)value, 14) == KERN_SUCCESS) {\n\n printf("%s\\n", test);\n //getchar();\n }\n\n if (vm_read(task, 0x7fff5fbff82a, sizeof(char) * 14, &buf, &sz) == KERN_SUCCESS) {\n\n memcpy(test1, (const void *)buf, sz);\n printf("%s", test1);\n }\n\n return 0;\n}\n我还尝试了 ptrace 和其他东西，这就是为什么我也包含其他库。 …
我如何在循环中使用getchar()？我现在有...
for (p=0; p<n_players; p++) {
...
fflush(stdin);
getchar();
}
但它不起作用......如果n_players为3,它只在最后执行getchar 2次...
for (p=0; p<n_players; p++) {
blank_start();
ascii_art_title();
printf("%s, tocca a te...\n",player_info[p].player_name);
srand(time(NULL));
random_speed = MIN_WHEEL_SPEED + rand()%MAX_WHEEL_SPEED;
move_wheel_pointer(random_speed, &pointer);
if (player_points(&wheel[pointer]) == 0){
player_info[p].points = wheel[pointer];
}
else {
player_info[p].points = 0;
}
printf("\nGuadagni %d punti...\n",player_info[p].points);
if (p<(n_players-1)) {
printf("\nOra tocca a te, giocatore %d\n",(p+2));
}
fflush(stdin);
getchar();
}
getchar跳过第一个循环
int check_row;
for (n=0; n<9; n++) {
used_numbers[n] = n+1;
}
for (row=0; row<3; row++) {
for (check_row=0; check_row<3; check_row++) {
used_numbers[(sudoku[row][check_row]-1)] = 0;
}
...
int sudoku [9] [9]声明为全局变量,used_numbers [9]声明为int.在数独矩阵中,行为0到2,列为0到2,每行中有数字> 0
此时我得到"浮点异常",如何解决这个问题？对不起,我的英语不好...