小编Til*_*ngh的帖子

我想在我的代码中使用快速输入和输出.我理解使用getchar_unlocked以下功能进行快速输入.

inline int next_int() {
    int n = 0;
    char c = getchar_unlocked();
    while (!('0' <= c && c <= '9')) {
        c = getchar_unlocked();
    }
    while ('0' <= c && c <= '9') {
        n = n * 10 + c - '0';
        c = getchar_unlocked();
    }
    return n;
}

有人可以解释我如何使用putchar_unlocked()功能快速输出？

我正在经历这个问题,有人说putchar_unlocked()可以用来快速输出.

我正在尝试使用python锁并试图理解它们。我有以下三个课程

LockMain.py

import time
from lock1 import *
from lock2 import *
import threading

class LockMain(threading.Thread):

    def __init__(self):
        threading.Thread.__init__(self)
        self.lock = threading.Lock
        self.obj1 = Lock1(self,"obj1")
        self.obj2 = Lock2(self,"obj2")
        threading.Thread(target=self.obj1.run).start()
        threading.Thread(target=self.obj2.run).start()

    def method1(self,str):
        with self.lock:
            print str+"Method1 entered"
            time.sleep(5)

    def method2(self,str):
        with self.lock:
            print str+"Method2 entered"
            time.sleep(5)

if __name__ == "__main__":
    obj = LockMain()

Lock1.py

import threading
import time

class Lock1(threading.Thread):
    def __init__(self,obj,str):
        threading.Thread.__init__(self)
        self.obj = obj
        self.str = str

    def run(self):
        count = 0
        while True:
            count += 1
            print …

我创建了一个矩阵类,并希望添加两个不同数据类型的矩阵.就像int和double返回类型的matrice应该是double.我怎样才能做到这一点？？？这是我的代码

template<class X>
class Matrix
{
..........
........
template<class U>
Matrix<something> operator+(Matrix<U> &B)
{
if((typeid(a).before(typeid(B.a))))
Matrix<typeof(B.a)> res(1,1);
else
Matrix<typeof(a)> res(1,1);
}

这里应该是什么"东西"???

还应该做什么,以便我可以使用"res"外面if else语句???

我在以下代码中检测到glibc,有人可以向我解释一下

#include<iostream>
using namespace std;
class Sample
{
public:
       int *ptr;
       Sample(int i)
       {
           ptr = new int(i);
       }
       void PrintVal()
       {
       cout << "The value is " << *ptr<<endl;
       }
       ~Sample()
       {
           cout<<"CALLED\n";
            delete ptr;
       }
};
void SomeFunc(Sample x)
{
    cout << "Say i am in someFunc " << endl;
    x.PrintVal();
    //cout<<*(s1.ptr)<<endl;
}
int main()
{
Sample s1=10;
cout<<*(s1.ptr)<<endl;
SomeFunc(s1);
cout<<"HERE\n";
cout<<*(s1.ptr)<<endl;
}

在这里调用cout<<*(s1.ptr)<<endl;glib被检测到.我无法理解的是,为什么即使没有为s1调用desructor,引用也会被删除.