小编jyo*_*oti的帖子

我正在尝试导入gmail联系人.我已成功获取access_token,但在尝试获取联系人浏览器时不断抛出错误.invalid_grant

我的代码如下.

用于身份验证和回调.

    authorize: function(req, res){
    var CLIENT_ID = '927112080821-vhsphqc79tb5ohfgpuvrp8uhh357mhad.apps.googleusercontent.com';
    var CLIENT_SECRET = 'gdgofL0RfAXX0in5JEiQiPW8';
    var SCOPE = 'https://www.google.com/m8/feeds';
        oa = new oauth.OAuth2(CLIENT_ID,
              CLIENT_SECRET,
              "https://accounts.google.com/o",
              "/oauth2/auth",
              "/oauth2/token");
    res.redirect(oa.getAuthorizeUrl({scope:SCOPE, response_type:'code', redirect_uri:'http://localhost:1234/callback'}));
  },
  callback: function(req, res){
    console.log(req.query.code);
    oa.getOAuthAccessToken(req.query.code, {grant_type:'authorization_code', redirect_uri:'http://localhost:1234/callback'}, function(err, access_token, refresh_token) {
    if (err) {
        res.end('error: ' + JSON.stringify(err));
    } else {
          getContactsFromGoogleApi(access_token);

        //res.write('access token: ' + access_token + '\n');
        //res.write('refresh token: ' + refresh_token);
        //res.end();
    }
    });

  },

用于导入联系人

function getContactsFromGoogleApi (access_token, req, res, next) {
console.log('access_token ' + access_token); …

我有以下函数写在server.js我一直得到 error: uncaughtException: Cannot call method 'redirect' of undefined

function(req, res) {
  async.waterfall([
    function(next){
      next(null, res);
    },

    function(next){
      next(null, res);
    },
    function(next, res){
      res.redirect('www.google.com')
    }
  ]);
}

从以下答案进行上述更改后我得到了,错误如下:

2014-09-04T13:56:08.678Z - error: uncaughtException: Object function (err) {
                if (err) {
                    callback.apply(null, arguments);
                    callback = function () {};
                }
                else {
                    var args = Array.prototype.slice.call(arguments, 1);
                    var next = iterator.next();
                    if (next) {
                        args.push(wrapIterator(next));
                    }
                    else {
                        args.push(callback);
                    }
                    async.nextTick(function () {
                        iterator.apply(null, args);
                    });
                }
            } has no method 'send'