小编Hac*_*lic的帖子

是否有命令行命令可以判断mod deflate是否在Apache上运行？

我很困惑 round 和 bround 在 Spark sql 中是如何工作的。

scala> spark.sql("select round(1.5, 0), bround(1.5, 0)").show()
+-------------+--------------+
|round(1.5, 0)|bround(1.5, 0)|
+-------------+--------------+
|            2|             2|
+-------------+--------------+


scala> spark.sql("select round(2.5, 0), bround(2.5, 0)").show()
+-------------+--------------+
|round(2.5, 0)|bround(2.5, 0)|
+-------------+--------------+
|            3|             2|
+-------------+--------------+


scala> spark.sql("select round(3.5, 0), bround(3.5, 0)").show()
+-------------+--------------+
|round(3.5, 0)|bround(3.5, 0)|
+-------------+--------------+
|            4|             4|
+-------------+--------------+

我有一个包含很多行的 file.txt 文件。我希望随机选择任何一行并通过电子邮件发送。这个循环了三次。

import smtplib,datetime,random

def mail(em):
    #print "yo"
    fromAddress = "atadmorecouth@gmail.com"
    toAddress = "atadmorecouth@gmail.com"
    subject = "WOW " + str(datetime.datetime.now())
    #print subject
    msg = em
    server=smtplib.SMTP("smtp.gmail.com", 587)
    server.starttls()
    password = "mypassword"
    server.login(fromAddress, password)
    server.sendmail(fromAddress, toAddress, msg)
    #print server.sendmail(fromAddress, toAddress, msg)


for i in range(0,3):
    em=str(random.choice(list(open('file.txt'))))
    mail(em)

这段代码不起作用。登录一切都很好。我注意到的唯一问题是 server.sendmail(fromAddress, toAddress, msg) 返回一个空的 {} 对此可能有什么解决办法？首先问题出在哪里？我已经在终端中运行了 mail() 函数，看起来工作正常。所有文件都托管在这里

在我的kafka集群中有超过2k个主题，每个主题有5个分区。我只想列出没有领导者的分区。

我可以使用以下语法检查每个主题：

kafka-topics.sh --describe --topic <topic_name> --zookeeper <zookeeper_ip>:port

但问题是有2k+主题，无法手动完成。我还可以编写一个脚本来循环每个主题并获取没有领导者的分区。但我对获取信息的有效方式感兴趣。

我有一个目录,其中包含许多具有以下格式的文件:

1 or 2 numbers_S followed by 1 or 2 numbers_L001_R1 or R2_001.fastq

Examples: 1_S1_L001_R1_001.fastq or 14_S14_L001_R2_001.fastq

我希望文件名是这样的: 1_R1.fastq 14_R2.fastq

我已经想出了regexp反映文件名的内容,并且可以成功地进行搜索和替换TextWrangler.以下是我提出的正则表达式:

Search: (\d+)\wS\d+\wL001\w(R\d)\w001(\.fastq)
Replace: \1_\2\3 (or $1_$2$3 depending on the program)

但是,我想知道如何使用简单的Python脚本批量重命名文件.我很感激任何建议.

谢谢!

我目前正在研究项目，我的项目工作正常并且可以正常工作。但是我想在跑步时取消警告sbt compile。当我运行时，sbt compile我不希望我的终端显示警告。

[warn] /Users/kumarshubham/Documents/repositories/alice/app/misc/QueryDB.scala:14: imported `QueryString' is permanently hidden by   definition of class QueryString in package misc
[warn] import misc.QueryString
[warn]             ^
[warn] /Users/kumarshubham/Documents/repositories/alice/app/misc/QueryDB.scala:26: method apply in trait WithResult is deprecated: Use   [[fold]], [[foldWhile]] or [[withResult]] instead, which manages resources and memory
[warn]       val resultSet = query().map(
[warn]                       ^
[warn] /Users/kumarshubham/Documents/repositories/alice/app/misc/QueryDB.scala:58: method apply in trait WithResult is deprecated: Use [[fold]], [[foldWhile]] or [[withResult]] instead, which manages resources and memory
[warn]       val resultSet = query().map(
[warn] …

>>> a = "2016-03-22 12:33:45.7565"
>>> datetime.datetime.strptime(a, "%Y-%m-%d %H:%M:%f")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/_strptime.py", line 328, in _strptime
    data_string[found.end():])
ValueError: unconverted data remains: .7565
>>> datetime.datetime.strptime(a, "%Y-%m-%d %H:%M:%S")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/_strptime.py", line 328, in _strptime
    data_string[found.end():])
ValueError: unconverted data remains: .7565

我已经使用%S和%f,但我怎么能应付秒钟,如果是类型float？

任何帮助,将不胜感激

int value =5;
void testPointer( int* pa, int* pb) {

*pa = *pb +5;
*pb = value;
value += 10;
}

我如何区分两者？我不明白

我正在学习 C 中的命令行参数。有一个部分我应该用 argv[i] 的位置定义 char 变量。我尝试使用argv[2]，但它显示一些警告( warning: initialization of 'char' from 'char *' makes integer from pointer without a cast [-Wint-conversion] )

每当我这样做时argv[2][0]，它确实有效。

为什么最后有一个0。对我来说这似乎是一个二维数组。

#include <stdio.h>
#include <stdlib.h>
int main(int argc,  char *argv[])
{
    int a, b, sum = 0 ;
    char operate = argv[2][0] ; //I tried running it by using argv[2], but it showing a conversion error
    // warning: initialization of 'char' from 'char *' makes integer from pointer without a cast …

我正在学习 C 语言中的函数，但遇到了一个问题。

这是代码：

#include <stdio.h>
#include <stdlib.h>

void equivalenza(int, int , int);

int main()
{
    int ore, minuti, secondi;
    printf("Inserisci ore, minuti e secondi (hh-mm-ss): ");
    scanf("%d-%d-%d", ore, minuti, secondi);
    equivalenza(ore, minuti, secondi);
    return 0;
}

void equivalenza(int ore, int minuti, int secondi)
{
    secondi = secondi + ore*3600;

    secondi = secondi + minuti*60;

    printf("\nSecondi = %d", secondi);
}

输出只是没有启动我认为的功能。

Inserisci ore, minuti e secondi (hh-mm-ss): 34-32-52

Process returned -1073741819 (0xC0000005)   execution time : 13.287 s