在第69页的"Git:每个人的版本控制.初学者指南"一书中,有一个建议:"作为替代git pull,我们也可以使用git fetch后跟git merge @{u}".
@{u}这里的意思是什么？
在Google中搜索git merge @{u}提供了此页面的链接http://mislav.uniqpath.com/2013/02/merge-vs-rebase/其中@{u}也可以找到.
我跑git pull两次并得到以下内容:
$ git pull
remote: Counting objects: 1, done.
remote: Total 1 (delta 0), reused 0 (delta 0)
Unpacking objects: 100% (1/1), done.
From git.assembla.com:my-project
da3f54c..bb335a4 master -> origin/master
Updating 5934c67..bb335a4
Fast-forward
$ git pull
Already up-to-date.
如何理解这个输出？
标题与列宽不对齐.JsFiddle.
我正在使用:
这是我正在使用的代码:
JS:
$(document).ready(function() {
var aoColumns = [null,null,null,null,null,null,null,null,null,null,null];
var oTable = $('#example').dataTable( {
"sScrollX": "100%",
"sScrollXInner": "150%",
"bPaginate": false,
"bAutoWidth": false,
"aoColumns": aoColumns
} );
var oFC = new FixedColumns( oTable, {
"iLeftColumns": 4
} );
oTable.fnAdjustColumnSizing();
});
HTML:
<body>
<div class="container">
<table width="100%" cellpadding="0" cellspacing="0" border="1" id="example">
<thead>
<tr>
<th rowspan="2">Branch</th>
<th rowspan="2">Object</th>
<th rowspan="2">Address</th>
<th rowspan="2">Count</th>
<th colspan="7">Availability</th>
</tr>
<tr>
<th>15</th>
<th>16</th>
<th>17</th>
<th>18</th>
<th>19</th>
<th>20</th>
<th>21</th>
</tr> …在包含项目的文件夹中运行以下命令:
$ xcodebuild -target MyCocoaFramework -configuration Debug -scheme MyCocoaFramework clean build | tee xcodebuild.log
$ oclint-xcodebuild
$ oclint-json-compilation-database
$
没有显示任何内容.这种方法适用于Cocoa应用程序.
$ xcodebuild -target MyCocoaApplication -configuration Debug -scheme MyCocoaApplication clean build | tee xcodebuild.log
$ oclint-xcodebuild
$ oclint-json-compilation-database
/a/b/c/d.m:181:5: redundant local variable P3
/a/b/c/d/e.m:193:5: redundant local variable P3
/a/b/c/d.m:104:1: long line P3 Line with 112 characters exceeds limit of 100
什么应该改变为Cocoa框架工作？
以下代码5个具有不同优先级的线程正在竞争访问具有8个内核的CPU(Mac OS X 10.8.5,Mono).每个线程增加其计数器.
using System;
using System.Threading;
class PriorityTesting
{
static long[] counts;
static bool finish;
static void ThreadFunc(object iThread)
{
while(true)
{
if(finish)
break;
counts[(int)iThread]++;
}
}
static void Main()
{
counts = new long[5];
Thread[] t = new Thread[5];
for(int i=0; i<t.Length; i++)
{
t[i] = new Thread(ThreadFunc);
t[i].Priority = (ThreadPriority)i;
}
// ????????? ??????
for(int i=0; i<t.Length; i++)
t[i].Start(i);
// ???? ??????? ??????????? ?????????? 10 c
Thread.Sleep(10000);
// ?????? ? ??????????
finish = true;
// ??????? …c# mono multithreading task-parallel-library thread-priority
我试图通过局部变量获得线程结果.
有代码:
static void Main()
{
long res1 = 0, res2 = 0;
long n1 = 5000, n2 = 10000;
Thread t1 = new Thread(() =>
{
res1 = Factorial(n1);
});
Thread t2 = new Thread(() => { res2=Factorial(n2); });
t1.Start();
t2.Start();
t1.Join();
t2.Join();
Console.WriteLine("Factorial of {0} equals {1}", n1, res1);
Console.WriteLine("Factorial of {0} equals {1}", n2, res2);
}
输出:
Factorial of 5000 equals 0
Factorial of 10000 equals 0
为什么这段代码返回0？
这是阶乘函数:
static long Factorial(long n)
{
long res = …c# ×2
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