小编jor*_*oro的帖子

我有一个工作查询,我需要通过使用常量枚举值进行过滤来修改.

现在它看起来像这样:

public static final String venueQuery = 
       "select distinct v from package.Venue v "
        + "<some joins here> "
        + "WHERE v.venueType = package.enums.VenueType.VOUCHER_PROVIDER ";

以这种方式更改数据会导致

org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token

列定义如下:

@Enumerated(EnumType.STRING)
@Column(name = "venue_type")
private VenueType venueType;

枚举定义看起来像这样:

public enum VenueType {
    RESTAURANT, BAR, CAFE, FUN_CLUB, VOUCHER_PROVIDER
}

我确信查询的其他部分工作正常,因为删除它后,不会抛出任何异常.

是否有在HQL查询中设置常量枚举值的技巧？

我从maven收到此错误消息:

[ERROR] Failed to execute goal on project battleships: Could not resolve dependencies for project com.miteff.travelex:battleships:wa
r:2.0.0-BUILD-SNAPSHOT: The following artifacts could not be resolved: javax.jms:jms:jar:1.1, com.sun.jdmk:jmxtools:jar:1.2.1, com.s
un.jmx:jmxri:jar:1.2.1: Could not transfer artifact javax.jms:jms:jar:1.1 from/to java.net (https://maven-repository.dev.java.net/no
nav/repository): Cannot access https://maven-repository.dev.java.net/nonav/repository with type legacy using the available connector
 factories: BasicRepositoryConnectorFactory: Cannot access https://maven-repository.dev.java.net/nonav/repository with type legacy u
sing the available layout factories: Maven2RepositoryLayoutFactory: Unsupported repository layout legacy -> [Help 1]
[ERROR]
[ERROR] To see the full stack trace of the errors, …

我有名字,工资和员工部门的数据库.我需要一个查询来获得每个部门薪水最高的员工.

数据库:

create table test(
    employee_name VARCHAR(255),
    department VARCHAR(255),
    salary INT  
);

数据:

INSERT INTO test(employee_name, department, salary) VALUES 
("John", "DepartmentA", 1500),
("Sarah","DepartmentA", 1600),
("Romel","DepartmentA", 1400),
("Victoria","DepartmentB", 1400),
("Maria",   "DepartmentB", 1600);

我的尝试:

1.1 WHERE MAX(薪水)=工资GROUP BY部门

SELECT employee_name, salary FROM test WHERE MAX(salary) = salary GROUP BY department;
ERROR 1111 (HY000): Invalid use of group function

1.2.当我用硬编码值替换MAX(薪水)时,它按预期工作:

SELECT employee_name, salary FROM test WHERE 1600 = salary GROUP BY department;
+---------------+--------+
| employee_name | salary |
+---------------+--------+
| Sarah         |   1600 …