当我尝试创建包含不同表的视图时,我收到以下错误:第1行出错:ORA-01031权限不足.
谁能告诉我可能是什么问题.我尝试按照这里提到的另一个stackoverflow帖子,但它与不同的模式有关.
因为我是新来的,请告诉我.
我的查询如下:
原始问题:创建一个视图以选择员工ID,员工姓名,雇用日期和部门编号.
我的解决方案
CREATE VIEW SIMPVIEW AS
SELECT EMPNO, ENAME, HIREDATE,DEPTNO
FROM EMP;
Run Code Online (Sandbox Code Playgroud) 我被要求编写一个程序(主要是一种方法)来改组一副牌.我写了以下程序:
public class Deck {
////////////////////////////////////////
// Data Members
////////////////////////////////////////
private Card[] cards; // array holding all 52 cards
private int cardsInDeck; // the current number of cards in the deck
public static final int DECK_SIZE = 52;
/**
* Shuffles the deck (i.e. randomly reorders the cards in the deck).
*/
public void shuffle() {
int newI;
Card temp;
Random randIndex = new Random();
for (int i = 0; i < cardsInDeck; i++) {
// pick a random index …Run Code Online (Sandbox Code Playgroud) 请考虑以下代码:
public class SentenceReversal {
/**
* @param args
*/
public static void main(String[] args) {
String[] parts = "This is an interview Question".split("\\b");
StringBuilder sb = new StringBuilder();
for (int i = parts.length; i --> 0 ;) {
sb.append(parts[i]);
}
System.out.println("[" + sb.toString() + "]");
}
}
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"\ b"在分割功能中做了什么?删除它会产生以下结果(这意味着只使用split("")):
[noitseuQ weivretni na si sihT]
另外,` - >'运算符在for循环中做了什么?我不太明白.请帮助我理解我的问题.
谢谢
我正在通过coldfusion代码并遇到以下信息.我不明白其中的一部分.我的问题如下:
码:
<cfif FINDNOCASE( "xyz.seta", "#CGI.SERVER_NAME#") GT 0 >
<cfset PublicPath = "abcxyz/NEW_abc/Public">
<cfset SessionPath = "abcxyz/NEW_abc/Session">
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我知道FINDNOCASE用于从指定的起始位置查找字符串中第一次出现子字符串.
Function Syntax: FindNoCase(substring, string [, start ])
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1)所以,在我的例子中,xyz.seta从"#CGI.SERVER_NAME#"开始搜索子字符串?我在这迷茫吗?
2)关于PublicPath和SessionPath定义的问题:
当我检查服务器时(使用VNC Viewer登录后),只有我可见的文件夹是Public和Session.我在哪里可以找到它之前的路径?在提出这样的问题之前,请澄清或告诉我是否需要学习更多内容.
谢谢
请考虑以下链接列表代码.基本上我在LinkedList类中创建了三个节点并尝试显示内容,但我在DisplayLinkedList()方法中做错了.现在我的输出如下:
B
C
null
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我想按如下方式显示:A B C.
分别.谁能告诉我DisplayLinkedList()方法中我错在哪里?
package MyPackage;
class Node {
String data;
Node next;
public Node(String data, Node next){
this.data = data;
this.next = next;
}
public String getData(){
return data;
}
public Node getNext(){
return next;
}
public void setNext(Node n){
next = n;
}
public String toString() {
return this.data;
}
}
// CREATING LINKED LIST BACKWARDS AND APPLYING SOME OPERATIONS ON IT
class LinkedList{
Node cNode = new Node("C", null);
Node bNode = new …Run Code Online (Sandbox Code Playgroud) 以下QoQ的倾销结果非常好:
<cfquery datasource = "XX.XX.X.XX" name="master2">
SELECT DATE(Timedetail) as FIRSTCONN
, count(Timedetail) as FIRSTOccurances
, EVENTS
FROM MyDatabase
WHERE EVENTS = "FIRST" GROUP BY FIRSTCONN
<!--- LIMIT 0,10 --->;
</cfquery>
<cfdump var="#master2#">
<cfquery dbtype="query" name="detail2">
SELECT *
FROM master2
WHERE FIRSTCONN >= <cfqueryparam value="#startdate#" cfsqltype="cf_sql_date">
AND FIRSTCONN < <cfqueryparam value="#enddate#" cfsqltype="cf_sql_date">;
</cfquery>
Dumping Result: <cfdump var="#detail2#"><cfabort>
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但是,当我尝试在QoQ上使用以下检查时:
Dumping Result: <cfdump var="#detail2.FIRSTCONN#"><cfabort>
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我没有看到完整的FIRSTCONN值列表.相反,我只看到一行:
Run Code Online (Sandbox Code Playgroud)Dumping Result: {ts '2013-06-29 00:00:00'}
理想情况下,我应该看到FIRSTCONN浏览器中所有内容的列表,不应该吗?
我编写了一个代码来从排序数组中查找中间元素.这是我的代码的一部分:
Java Code:
int[] a = {1,2,3,4,5};
int x = a.length;
if (x % 2 != 0){
int mid = 0 + x/2;
System.out.println("The Middle Element is : " + a[mid]);
}
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我正在获得正确的输出,但想知道我应该在上面的代码的else条件下写什么?换句话说,如果a.length是偶数,我该怎么做才能找到一个中间元素?这可能吗?
我在abc.cfm中运行以下表单.
//参数定义
<cfparam name="startdate" default="#DateFormat(dateAdd('d',-40,now()), 'yyyy-mm-dd')#">
<cfparam name="enddate" default="#DateFormat(dateAdd('d',-1,now()), 'yyyy-mm-dd')#">
<cfform format="HTML" action="datedownload.cfm" method="get" >
<cfformgroup type="horizontal">
<cfinput type="dateField" name="startdate" width="100" value="#startdate#">
<cfinput type="dateField" name="enddate" width="100" value="#enddate#">
<cfinput name="submitApply" type="submit" value = "Apply">
<cfinput type="button" name="download" value="Download" onclick="window.location.href='datedownload.cfm?startdate=#form.startdate#&enddate=#form.enddate#path=http://abc.xyz.com/username/July30/datedownload.cfm'">
</cfformgroup>
</cfform>
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使用datedownload.cfm中的以下代码,一切都正常打印
Startdate: <cfdump var = "#startdate#">
End Date :<cfdump var = "#enddate#">
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除此之外,Enddate正在打印完整路径,如下所示:
Startdate: 2013-06-20 End Date : 2013-07-29path=http://abc.xyz.com/username/July30/datedownload.cfm
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如何从路径中删除东西?
我按照本教程创建了简单的 JMS 相关应用程序,但我不断收到异常(堆栈跟踪粘贴在下面)
我尝试查看其他类似的线程,在许多地方看起来人们要求在界面中添加 @Repository 注释,但我的界面没有扩展任何存储库。
我的代码如下所示:
客户端
public interface JmsClient {
public void send(String msg);
public String receive();
}
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JmsClientImpl.java
@Service
public class JmsClientImpl implements JmsClient{
@Autowired
JmsConsumer jmsConsumer;
@Autowired
JmsProducer jmsProducer;
@Override
public void send(String msg) {
jmsProducer.send(msg);
}
@Override
public String receive() {
return jmsConsumer.receive();
}
}
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JmsConsumer.java
@Component
public class JmsConsumer {
@Autowired
JmsTemplate jmsTemplate;
@Value("${jms.queue.destination}")
String destinationQueue;
public String receive(){
return (String)jmsTemplate.receiveAndConvert(destinationQueue);
}
}
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网络控制器.java
@RestController
public class WebController {
@Autowired
JmsClient jsmClient; …Run Code Online (Sandbox Code Playgroud) 我在编辑器中的以下代码工作正常。
import React, { Component } from "react";
import { render } from "react-dom";
import "jqwidgets-scripts/jqwidgets/styles/jqx.base.css";
import JqxButton from "jqwidgets-scripts/jqwidgets-react-tsx/jqxbuttons";
import * as ReactDOM from "react-dom";
import JqxWindow from "jqwidgets-scripts/jqwidgets-react-tsx/jqxwindow";
import JqxInput from "jqwidgets-scripts/jqwidgets-react-tsx/jqxinput";
import JqxChart, {
IChartProps
} from "jqwidgets-scripts/jqwidgets-react-tsx/jqxchart";
import JqxGrid, {
IGridProps,
jqx
} from "jqwidgets-scripts/jqwidgets-react-tsx/jqxgrid";
import JqxTabs from "jqwidgets-scripts/jqwidgets-react-tsx/jqxtabs";
import JqxDropDownList, {
IDropDownListProps
} from "jqwidgets-scripts/jqwidgets-react-tsx/jqxdropdownlist";
interface AppProps {}
interface AppState {
name: string;
}
interface IProps extends IGridProps {
rendertoolbar1: IGridProps["rendertoolbar"];
dropdownlistSource: IDropDownListProps["source"]; …Run Code Online (Sandbox Code Playgroud) java ×5
coldfusion ×3
coldfusion-8 ×2
arrays ×1
cfform ×1
coldfusion-9 ×1
collections ×1
jsx ×1
linked-list ×1
oracle ×1
oracle11g ×1
reactjs ×1
sorting ×1
spring ×1
spring-boot ×1
sql ×1
view ×1