小编Eva*_*van的帖子

我已经创建了一个表单.如果接收到所有信息并且似乎工作,但是当我检查文本文件时没有写入任何内容,并且它只允许我在错误输出之前运行表单两次.有谁看到了问题？

const string FileName = "Friends.txt";
Friend friend = new Friend();
FileStream file = new FileStream(FileName, FileMode.OpenOrCreate, FileAccess.Read, FileShare.ReadWrite);
FileStream file2 = new FileStream(FileName, FileMode.Append, FileAccess.Write, FileShare.ReadWrite); 

public Form1()
{
    InitializeComponent();
}

private void enter_Click(object sender, EventArgs e)
{
    StreamWriter write = new StreamWriter(file2);

    try
    {
        friend.FirstName = firstName.Text;
        friend.LastName = lastName.Text;
        friend.PhoneNumber = phoneNumber.Text;
        friend.Month = Convert.ToInt32(birthMonth.Text);
        friend.Day = Convert.ToInt32(birthday.Text);
        write.WriteLine(friend.ToString());
        MessageBox.Show("Wrote " + friend.ToString() + " to file.");
    }
    catch(Exception error)
    {
        MessageBox.Show(error.Message + " Please reenter the …