小编dan*_*nik的帖子

我弹簧安全登录表单我们有以下表格

<form name='f' action='/j_spring_security_check' method='POST'> 
 <table> 
    <tr><td>User:</td><td><input type='text' name='j_username' value=''></td></tr> 
    <tr><td>Password:</td><td><input type='password' name='j_password'/></td></tr> 
    <tr><td colspan='2'><input name="submit" type="submit"/></td></tr> 
    <tr><td colspan='2'><input name="reset" type="reset"/></td></tr> 
  </table> 
</form>

我知道如何修改此表单上的action属性(使用 login-processing-url="/login")我的问题是如何更改j_username和j_password标签名称,是用户名和密码？

我有以下JSF 2.1页面

<h:selectOneRadio value="#{userBean.newUser}">
    <f:selectItem itemValue="0" itemLabel="new User" />
    <f:selectItem itemValue="1" itemLabel="existing User" />
</h:selectOneRadio>
<br />
<h:inputText value="#{userBean.customerId}" id="customerId" />
<h:message for="customerid" />
<br />
<h:inputText value="#{userBean.firstName}" id="firstName" />
<h:message for="fisrtName" />
<br />
<h:inputText value="#{userBean.lastName}" id="lastName" />
<h:message for="lastName" />
<br />
<h:commandButton value="Submit" action="#{userBean.login}" />

这是我的豆子:

public class UserBean {

    private String customerId;
    private String newUser= "0";
    private String firstName;
    private String lastName;

    // Getters and seeters ommited.
}

我需要通过以下方式验证此表单:

如果选择"新用户"单选按钮,则应验证所有表单输入.如果选择"现有用户",我只需要验证客户ID.

我尝试了Hibernate验证,我还通过实现javax.faces.validator.Validator接口尝试了自定义验证器.

我能以某种方式实现这样的功能吗？

我正在尝试编写一个非常简单的程序,它将模仿简单的DeadLock,其中线程A等待由线程B锁定的资源A,线程B等待由线程A锁定的资源B.

这是我的代码:

//it will be my Shared resource
public class Account {
    private float amount;

    public void debit(double amount){
        this.amount-=amount;
    }

    public void credit(double amount){
        this.amount+=amount;
    }

}  

这是我的runnable,它在上面的资源上执行Operation:

public class BankTransaction implements Runnable {
    Account fromAccount,toAccount;
    float ammount;
    public BankTransaction(Account fromAccount, Account toAccount,float ammount){
        this.fromAccount = fromAccount;
        this.toAccount = toAccount;
        this.ammount = ammount;
    }

    private void transferMoney(){
        synchronized(fromAccount){
            synchronized(toAccount){
                fromAccount.debit(ammount);
                toAccount.credit(ammount);
                try {
                    Thread.sleep(500);
                } catch (InterruptedException e) {
                e.printStackTrace();
                }
                System.out.println("Current Transaction Completed!!!");
            }
        }
    }

    @Override
    public …

我需要创建Job,它将:

• 2012年12月20日开始
• endDate = 12/31/2017
• 将在周日和周一每两周举行一次
• 下午5点开火.

这个cron表达式有效吗？

Date start = 12/20/2012;
Date endDate = 12/31/2017;
SimpleTrigger trigger = newTrigger()
    .withIdentity("trigger3", "group1")
    .startAt(startDate) 
    .withSchedule(cronSchedule("* * 17 0 0/2 *,SUN,MON").build())
    .endAt(endDate)
    .build;

请指教.

我正在尝试使用soap标头发送SOAP请求,如下所示:

<SOAP-ENV:Header>
<Security xmlns="http://www.xxx.org/xxx/2003/05">
<UsernameToken><Username>yyyy</Username><Password>xxx</Password>
</UsernameToken></Security></SOAP-ENV:Header>

为了做到这一点,我正在使用添加标题元素 SoapActionCallback

SoapActionCallback actionCallBack = new SoapActionCallback("https://aaa.com/bbb.asmx") {
            public void doWithMessage(WebServiceMessage msg) {
                SoapMessage smsg = (SoapMessage) msg;
                smsg.setSoapAction("http://www.xxx.org/yyy/2003/05/SessionCreate");
                SoapHeaderElement security = smsg.getSoapHeader().addHeaderElement(new QName("http://www.xxx.org/yyy", "Security"));
                security.setText("<UsernameToken><Username>yyyy</Username><Password>xxx</Password></UsernameToken>");
            }
        };

我的问题是soap标题看起来像这样

<SOAP-ENV:Header><Security xmlns="http://www.xxx.org/yyy/2003/05">&lt;UsernameToken&gt;&lt;Username&gt;yyyyy&lt;/Username&gt;&lt;Password&gt;xxxx&lt;/Password&gt;&lt;/UsernameToken&gt;</Security></SOAP-ENV:Header>

结果我的请求失败了:

如何正确添加此消息？

在我的测试场景中，我正在轮询用户会话以获取可能的响应。由于产品行为，在收到响应之前多次收到 503 是正常的，这就是我最多重试 5 次的原因。

tryMax(5){
      exec(http("Poll user")
        .get("/something.html")
        .queryParamMap(Map("NC" -> "true", "data" -> "true", "v" -> "1"))
        .check(
          status.is(200))
      )}

现在'当我查看统计数据时，我看到 4 个失败的请求：

[--------------------------------------------------------------------------]  0%
          waiting: 0      / active: 80     / done:0
---- Requests ------------------------------------------------------------------
> Global                                                   (OK=1771   KO=4     )
> Form Login                                               (OK=80     KO=0     )
> **********************                                   (OK=80     KO=0     )
> Agent Base                                               (OK=80     KO=0     )
> Login                                                    (OK=80     KO=0     )
> Set availability to Online                               (OK=80     KO=0     )
> Poll session                                             (OK=1291   KO=4     )
---- Errors -------------------------------------------------------------------- …

我有以下课程:

public class Student {
    private Long id  ;
    private String firstName;
    private String lastName;
private Set<Enrollment> enroll = new HashSet<Enrollment>();
//Setters and getters
}

public class Enrollment {
    private Student student;
    private Course course;
    Long enrollId;

//Setters and Getters
}

我有Struts2控制器,我想只返回Class Student的Serialized实例.

@ParentPackage("json-default")
public class JsonAction extends ActionSupport{

private Student student;

@Autowired
DbService dbService;

public String populate(){
    return "populate";
}

@Action(value="/getJson", results = {
        @Result(name="success", type="json")})
public String test(){
    student =  dbService.getSudent(new Long(1));
    return "success";
}

@JSON(name="student")
public Student …

我有这种@OneToOne Hibernate relationShip

public class Address implements Serializable {

    private String id;
    private String city;
    private String country;
//setter getters ommitted
}

public class Student implements Serializable {

    private String id;
    private String firstName;
    private String lastName;    
    private Address address;
}

地址项目映射为LAZY.

现在我想使用获取用户及其地址

session.load(Student.class,id);

在我的daoService中.

然后我从Spring MVC控制器返回JSON:

@RequestMapping(value="/getStudent.do",method=RequestMethod.POST)
    @ResponseBody
    public Student getStudent(@RequestParam("studentId") String id){
        Student student = daoService.getStudent(id);
        return student;
    }

不幸的是,由于懒惰的clasees它没有工作,我失败了:

org.codehaus.jackson.map.JsonMappingException: No serializer found for class org.hibernate.proxy.pojo.javassist.JavassistLazyInitializer and no properties discovered to create BeanSerializer (to avoid exception, disable …

我有以下课程:

package x.y.z;

public class MyClass{
public void someMethod(SomeObject object){
//do somethinng
}

public void {
//do somethinng
}

}

现在我想@PointCut只设置方法someMethod(SomeObject object, int param1)

我该怎么做？

更新我正在尝试

@Pointcut("execution(x.y.z.MyClass.someMethod(x.y.z.SomeObject))") but I'm getting not well formed pointcut exception.

我正在尝试使用递归来解决迷宫问题.它被宣布了Cell [][] maze.

public class Cell {
    private Wall left;
    private Wall right;
    private Wall up;
    private Wall down;
    private boolean end;

    // Setters and getters not shown
}

如果Wall单元格的某一侧没有,那么它有值null,否则它指的是一个Wall对象.Wall参考是一致的:与单壁相邻的两个单元都用适当的字段表示它.如果缺少墙,则两个相邻的单元都具有相应的null条目.这是搜索:

public boolean solveMaze(Cell[][] maze, int i, int j) {

    if (maze[i][j].isEnd()){
        System.out.println(maze[i][j].toString());
        return true;
    }
    if (maze[i][j].getDown() == null) {
        return solveMaze(maze, i, j + 1); 
    }
    if (maze[i][j].getUp() == null) {
        return solveMaze(maze, i, j - 1) …