小编sou*_*cse的帖子

在iOS 8中,我遇到了从相机捕获图像的问题,直到现在我正在使用此代码

UIImagePickerController *controller=[[UIImagePickerController alloc] init];
controller.videoQuality=UIImagePickerControllerQualityTypeMedium;
controller.delegate=(id)self;
controller.sourceType=UIImagePickerControllerSourceTypeCamera;
[self presentViewController:controller animated:YES completion:nil];

但是在iOS 8中我得到了这个:

Snapshotting a view that has not been rendered results in an empty snapshot. Ensure your view has been rendered at least once before snapshotting or snapshot after screen updates.

我曾尝试与所提供的解决方案这个帖子用

@property (strong,nonatomic)UIImagePickerController *controller;

_controller=[[UIImagePickerController alloc] init];
_controller.videoQuality=UIImagePickerControllerQualityTypeMedium;
_controller.delegate=(id)self;
_controller.sourceType=UIImagePickerControllerSourceTypeCamera;
_[self presentViewController:controller animated:YES completion:nil];

还有这个

...
controller.modalPresentationStyle=UIModalPresentationFullScreen;
or
controller.modalPresentationStyle=UIModalPresentationCurrentContext;
...

还有这个

double delayInSeconds = 0.1;
dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, delayInSeconds * NSEC_PER_SEC);
dispatch_after(popTime, dispatch_get_main_queue(), …

有没有选择停止在iOS 8中显示表情符号键盘？它不适用于小键盘和安全文本,但对于电子邮件,它就在那里.如果无法禁用它如何从表情符号中获取字符串值？

嗨,我想在我的iOS应用程序上集成谷歌+登录.我按照此链接的说明进行操作.

这些示例工作正常,但当我尝试在我的应用程序上实现时,它就是这样

errorTerminating app due to uncaught exception 'NSInvalidArgumentException', reason: '+[NSBundle gpp_registerFonts]: unrecognized selector sent to class 0x16af620'

我添加了以下框架 Image Any help

代码:在我的视图的viewdidload中

GPPSignIn *signIn = [GPPSignIn sharedInstance];
signIn.shouldFetchGooglePlusUser = YES;
signIn.shouldFetchGoogleUserEmail = YES;  // Uncomment to get the user's email

// You previously set kClientId in the "Initialize the Google+ client" step
signIn.clientID = kClientId;
signIn.scopes = [NSArray arrayWithObjects:
                 kGTLAuthScopePlusLogin, // defined in GTLPlusConstants.h
                 nil];
// Optional: declare signIn.actions, see "app activities"
signIn.delegate = self;

之后我添加了这个功能

- …

我遇到了以下laravel代码的问题,在Laravel中执行时没有返回任何行:

$entries = DB::table('chemlog')
        ->where('timestamp', '>=','DATE_SUB(NOW(), INTERVAL 1 DAY')
        ->orderBy('timestamp','desc')
        ->get();

当我在MySQL控制台上执行以下操作时,它可以正常工作:

SELECT * FROM chemlog WHERE timestamp >= DATE_SUB(NOW(), INTERVAL 1 DAY)

Laravel的组装和我在控制台上写的内容有什么区别？

我正在使用:

PHP 5.5, MySQL 5.6, Laravel 4

我坚持这个非常基本的问题.如何将列表中的元组转换为列表.

例如,

[(23,5,6,4)]=>[23,5,6,4]

这是一个非常基本的问题,我使用for循环完成了这个.但有更好的方法吗？

  def make_list(item):
  ''' Helper for get_alert
  '''
  temp = []
  for inst in item:
     temp.append(inst)
  return temp