我有这个查询更新了比 2 天前更高的价格，但不起作用
@Transactional
@Modifying
@Query("update HotelDailyPrice hdp set hdp.price = (select avg (hp.price) "
+ "from HotelPrice hp where hp.id = ?1 and hp.updateDate > CURRENT_DATE - 2), hdp.day = ?2 ")
void updateDailyAveragePrice (Hotel hotel, String dayDate);
我试图使用一对多的关系但我因为这个错误而卡住了:
20:17:54,621 INFO [stdout] (default task-2) Hibernate: select user0_.user_id as user_id1_1_, user0_.nick as nick2_1_, user0_.password as password3_1_ from users user0_
20:17:54,655 INFO [stdout] (default task-2) Hibernate: select userrole0_.users as users3_1_0_, userrole0_.id as id1_0_0_, userrole0_.id as id1_0_1_, userrole0_.role as role2_0_1_, userrole0_.users as users3_0_1_ from user_roles userrole0_ where userrole0_.users=?
20:17:54,657 WARN [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (default task-2) SQL Error: 0, SQLState: 42883
20:17:54,658 ERROR [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (default task-2) B??D: operator ndoesnt exist: bytea = integer
我不知道为什么我会得到这个例外.我不在bytea任何地方使用运营商.下面,我提供了源代码:
User.java
@Entity
@Table(name = "users")
public class User …如果它们之间的差异小于10分钟,我想比较两个日期.我怎么做？
Date created = Date.parse('yyyy-MM-dd HH:mm:ss','2014-06-05 10:19:04')
Date now = new Date()
now.compareTo(created) gives me 1 but I want to compare the minute difference.
我正在开发一个程序,它使用返回的方法,Optional我需要迭代它并创建一个新对象.我怎么做？
import java.util.Optional;
class Info {
String name;
String profileId;
Info(String name, String profileId) {
this.name = name;
this.profileId = profileId;
}
}
class Profile {
String profileId;
String profileName;
Profile(String profileId, String profileName) {
this.profileId = profileId;
this.profileName = profileName;
}
}
class Content {
String infoName;
String profileName;
Content(String infoName, String profileName) {
this.infoName = infoName;
this.profileName = profileName;
}
public java.lang.String toString() {
return "Content{" + "infoName='" + infoName + '\'' + ", profileName='" + …