我在我正在处理的一些代码中找到了这个,我想知道这是做什么的
h = Hash.new {|hash, key| hash[key] = 0}
=> {}
我有这个php块
<?php switch ($_GET['class_id']) { ?>
<?php case 1: ?>
<img src="<?php print $result['standard_image'] == "" ? "/pre_config/css/images/blue-png2.png" : "/shop_possystems/image/{$result['standard_image']}" ?>" alt="" />
<?php break; ?>
<?php case 2: ?>
<img src="<?php print $result['business_image'] == "" ? "/pre_config/css/images/blue-png2.png" : "/shop_possystems/image/{$result['business_image']}" ?>" alt="" />
<?php break; ?>
<?php case 3: ?>
<img src="<?php print $result['premium_image'] == "" ? "/pre_config/css/images/blue-png2.png" : "/shop_possystems/image/{$result['premium_image']}" ?>" alt="" />
<?php break; ?>
<?php default: ?>
<img src="<?php print $result['standard_image'] == "" ? "/pre_config/css/images/blue-png2.png" : "/shop_possystems/image/{$result['standard_image']}" ?>" …我在这里有这个表格,我不希望他们在没有选择的情况下进入下一页
<form method="post" action="step2/" id="form1">
....
....
....
<input type="submit" class="submit notext" value="Next" />
这是我的jquery
$('.submit').click(function(e) {
var business = $(".business_type_select").find('.container strong').text();
alert(business);
if(business == "Select Business Type"){
alert("BusinessBusinessBusiness");
e.preventDefault;
return false;
}
});
任何想法我错过了让它停止提交
这似乎很容易,但我无法弄明白
$users_emails = array(
'Spence' => 'spence@someplace.com',
'Matt' => 'matt@someplace.com',
'Marc' => 'marc@someplace.com',
'Adam' => 'adam@someplace.com',
'Paul' => 'paul@someplace.com');
我需要获取数组中的下一个元素但我无法弄清楚...例如
如果我有
$users_emails['Spence']
我需要退回matt@someplace.com,如果是的话
$users_emails['Paul']
我需要从顶部开始并返回spence@someplace.com
我试过这个
$next_user = (next($users_emails["Spence"]));
这也是
($users_emails["Spence"] + 1 ) % count( $users_emails )
但他们不回报我所期待的
我把它添加到我的WordPress 页面
if (script.readyState && script.onload!==null){
script.onreadystatechange= function () {
if (this.readyState == 'complete') mce_preload_check();
}
}
和&&正在被关到
if (script.readyState && script.onload!==null){
我在WordPress HTML视图中粘贴了这个,我确定这很好,但WordPress一直在显示它.怎么解决这个问题？
可能重复:
在JavaScript中声明多个变量
我在jQuery中设置了一些变量,有人建议我这样做:
var $wrapper = that.parents(".wrapper"),
$prettyCheckBox0 = $wrapper.find(".prettyCheckbox small:eq(0)"),
$prettyCheckBox1 = $wrapper.find(".prettyCheckbox small:eq(1)"),
$prettyCheckBox2 = $wrapper.find(".prettyCheckbox small:eq(2)"),
standard = $prettyCheckBox0.parents("span").parents("label").prev("input").val(),
professional = $prettyCheckBox1.parents("span").parents("label").prev("input").val(),
premium = $prettyCheckBox2.parents("span").parents("label").prev("input").val();
虽然这有效,但我想知道是否有人有理由为什么选择逗号而不是分号.它是如何工作的？看起来它会导致语法错误.另外,为什么有一个var？
我有这个侧边栏代码
<li><a href="/restaurant_pos"><span>Restaurant POS Systems</span></a>
<ul>
<li><a href="/restaurant_pos">Restaurant POS Systems</a></li>
<li><a href="/bar_nightclub_pos">Bar and Nightclub POS Systems</a></li>
<li><a href="/bbq-restaurant-pos">BBQ Restaurant POS</a></li>
<li><a href="/bowling-alley-pos-system">Bowling Alley Point of Sale</a></li>
<li><a href="/cafe-pos">Cafe Point of Sale Systems</a></li>
<li><a href="/chinese-restaurant-pos">Chinese Restaurant POS Systems</a></li>
<li><a href="/fine-dining-pos">Fine Dining Point of Sale Systems</a></li>
....
....
ans我想在当前页面添加一个活动类,所以这就是我采用的方法
<li><a href="/restaurant_pos"><span>Restaurant POS Systems</span></a>
<ul>
<li><a <?php if($_SERVER['REQUEST_URI'] == '/restaurant_pos/'){
echo "class='active' ";
}
?> href="/restaurant_pos">Restaurant POS Systems</a></li>
<li><a
<?php if($_SERVER['REQUEST_URI'] == '/bar_nightclub_pos/'){
echo "class='active' ";
}
?>
href="/bar_nightclub_pos">Bar and Nightclub POS Systems</a></li> …我目前正在向heroku部署rails应用程序.该应用程序是rails 2.3.3,由于某种原因可能因为它不同的ruby我没有得到一个奇怪的语法错误
这是我的错误
Downloading postal codes.
rake aborted!
/app/app/models/postal_code.rb:13: syntax error, unexpected ':', expecting keyword_then or ',' or ';' or '\n'
when Integer: first(:conditions => { :code => code })
^
/app/app/models/postal_code.rb:14: syntax error, unexpected keyword_when, expecting keyword_end
when Hash: first(:conditions => {...
^
/app/app/models/postal_code.rb:59: syntax error, unexpected keyword_end, expecting $end
这是我的代码文件(postal_code.rb)
11 def self.get(code)
12 case code
13 when Integer: first(:conditions => { :code => code })
14 when Hash: first(:conditions => { :city => code[:city], :state => code[:state] … if !row[0].include? 'Changed database' || !row[0].starts_with? '---' || !row[0].include? "rows affected" || !row[0].nil? || !row[0] == ""
如果我做
if !row[0].include? 'Changed database'
它运作良好,但如果我做了多个条件,那么它就失败了这个错误
SyntaxError: /Users/tamer/Sites/active/app/models/account.rb:42: syntax error, unexpected tSTRING_BEG, expecting kTHEN or ':' or '\n' or ';'
...ase' || !row[0].starts_with? '---' || !row[0].include? "rows...
我在页面上有一堆复选框,我想为每个复选框传递两个值,如下所示....
<input name="class[]" value="first_value" data="second_value" type="checkbox" class="auto"/>
任何想法如何获取first_value和second_value过去PHP中的$ _POST
关于如何做到这一点的任何建议