小编Eli*_*ner的帖子

我正在尝试从Windows中的命令行执行Java程序.这是我的代码:

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;

public class CopyFile
{
    public static void main(String[] args)
    {

        InputStream inStream = null;
        OutputStream outStream = null;

        try
        {

            File afile = new File("input.txt");
            File bfile = new File("inputCopy.txt");

            inStream = new FileInputStream(afile);
            outStream = new FileOutputStream(bfile);

            byte[] buffer = new byte[1024];

            int length;
            // copy the file content in bytes
            while ((length = inStream.read(buffer)) > 0)
            {

                outStream.write(buffer, 0, length);

            }

            inStream.close();
            outStream.close();

            System.out.println("File is …

所以我想弄明白这一点.我做了一个名字的arraylist年龄必须按年龄,然后按名称排序(如果年龄相等)我确信有一个简单的方法来做到这一点,但我们的教训是要求我们使用接口.所以我到目前为止的是一个人名和年龄的数组列表,然后是一个人类,我可以从中检索信息.如何对要传递回主类的列表进行排序？PersonSorter:

import java.util.ArrayList;
import java.util.Collections;


public class PersonSorter
{
    public static void main(String[] args)
    {
        ArrayList<Person> people = new ArrayList<Person>();

        people.add(new Person("Linda", 63));
        people.add(new Person("Jacob", 5));
        people.add(new Person("Emily", 13));
        people.add(new Person("Jessica", 21));
        people.add(new Person("Emma", 5));
        people.add(new Person("Robert", 80));
        people.add(new Person("Jennifer", 43));

        // PRINT THE LIST OF PEOPLE BEFORE SORTING
        for (Person person : people)
        {
            System.out.println(person);
        }

        System.out.println();//space between the lists

        Collections.sort(people);

        // PRINT THE LIST OF PEOPLE AFTER SORTING
        for (Person person : people)
        {
            System.out.println(person);
        }
    }
} …