小编Ker*_*ert的帖子

我有以下格式的数据结构:

data_hash = [
    { price: 1, count: 3 },
    { price: 2, count: 3 },
    { price: 3, count: 3 }
  ]

有没有一种有效的方法来获得:price像数组一样的值[1,2,3]？

我想用RSpec测试一个模型,但我可能偶然发现了一个我无法找到的拼写错误.有人可以帮我一点吗？我长期以来一直在努力,只是找不到任何错误.先感谢您!

user_spec.rb

require 'spec_helper'

describe User do
     it "has a valid factory" do
        FactoryGirl.build(:user).should be_valid
     end
     it "is invalid without an e-mail"
     it "is invalid without a correct e-mail" 
     it "is invalid without a password" 
     it "is invalid without a matching password confrimation" 
end

user.rb

FactoryGirl.define do
    factory :user do |f|
        f.email "aabb@hh.de"
        f.password "ruby"
        f.password_confrimation "ruby"
    end
end

spec_helper.rb

# This file is copied to spec/ when you run 'rails generate rspec:install'
ENV["RAILS_ENV"] ||= 'test'
require File.expand_path("../../config/environment", __FILE__)
require …

我有一个由以下形式的哈希组成的数组:

[
  {:user=>"mike" etc},
  {:user=>"mike" etc},
  {:user=>"peter" etc},
  {:user=>"joe" etc}
]

是否有任何方便的方法根据用户密钥的值拆分组？最终结果应该是这样的:

[
  [{:user=>"mike" etc}, {:user=>"mike" etc}],
  [{:user=>"peter" etc}],
  [{:user=>"joe" etc}]
]

我正在尝试编写一些RSpec测试来测试我的应用程序,但我偶然发现了一些我找不到任何解决方案的问题.1)我正在尝试测试更新操作.这是我的代码:

        it "email is a new one" do
            put :update, id: @user, user: FactoryGirl.attributes_for(:user, :email=>"a@b.c")
            @user.reload
            @user.email.should == "a@b.c"
            puts @user.email
        end

这是UsersController更新操作:

  def update
    @user = User.find(params[:id])
    respond_to do |format|
      if @user.update_attributes(params[:user])
        format.html { redirect_to edit_user_path(@user), :notice => "Your settings were successfully updated."}
        format.json { head :no_content }
      else
        format.html { render action: "edit" }
        format.json { render json: @user.errors, status: :unprocessable_entity }
      end
    end
  end

这是错误:

 Failure/Error: @user.email.should == "a@b.c"
       expected: "a@b.c"
            got: "user16@example.com" (using ==)

很明显,测试没有改变用户的电子邮件.我从这里获取 …