我一直在关注https://serverless-stack.com/chapters/configure-cognito-user-pool-in-serverless.html 上的无服务器教程
我有以下无服务器 yaml snippit
Resources:
CognitoUserPool:
Type: AWS::Cognito::UserPool
Properties:
# Generate a name based on the stage
UserPoolName: ${self:custom.stage}-moochless-user-pool
# Set email as an alias
UsernameAttributes:
- email
AutoVerifiedAttributes:
- email
CognitoUserPoolClient:
Type: AWS::Cognito::UserPoolClient
Properties:
# Generate an app client name based on the stage
ClientName: ${self:custom.stage}-user-pool-client
UserPoolId:
Ref: CognitoUserPool
ExplicitAuthFlows:
- ADMIN_NO_SRP_AUTH
# >>>>> HOW DO I GET THIS VALUE IN OUTPUT <<<<<
GenerateSecret: true
# Print out the Id of the User Pool that is …我正在追踪我的Metal应用程序中的一些视觉弹出,并且相信这是因为我直接绘制到帧缓冲区,而不是后缓冲区
// this is when I've finished passing commands to the render buffer and issue the draw command. I believe this sends all the images directly to the framebuffer instead of using a backbuffer
[renderEncoder endEncoding];
[mtlCommandBuffer presentDrawable:frameDrawable];
[mtlCommandBuffer commit];
[mtlCommandBuffer release];
//[frameDrawable present]; // This line isn't needed (and I believe is performed by presentDrawable
几个谷歌后来,我还没有找到任何金属背缓冲的文档.我知道我可以自己滚动,但我不相信金属不支持后缓冲.
这是我如何设置CAMetalLayer对象的代码片段.
+ (id)layerClass
{
return [CAMetalLayer class];
}
- (void)initCommon
{
self.opaque = YES;
self.backgroundColor = nil;
...
}
-(id <CAMetalDrawable>)getMetalLayer
{
id …我有下面的着色器（为了长度和清晰度而删除了一些部分），并且希望找到更好的方法来做到这一点。我想将尺寸可变的纹理数组发送到我的金属着色器。我将对顶点位置进行一些计算，然后找出要使用的纹理。
目前我只是硬编码了一些东西并使用了几个 if 语句，但这很丑陋（而且我猜速度不快）。有什么方法可以计算i然后用作i纹理下标（如tex[i].sample）？
// Current code - its ugly
fragment half4 SimpleTextureFragment(VertextOut inFrag [[stage_in]],
texture2d<half> tex0 [[ texture(0) ]]
texture2d<half> tex1 [[ texture(1) ]]
texture2d<half> tex2 [[ texture(2) ]]
...
texture2d<half> texN [[ texture(N) ]]
)
{
constexpr sampler quad_sampler;
int i = (Compute_Correct_Texture_to_Use);
if(i==0)
{
half4 color = tex0.sample(quad_sampler, inFrag.tex_coord);
}
else if(i==1)
{
half4 color = tex1.sample(quad_sampler, inFrag.tex_coord);
}
...
else if(i==n)
{
half4 color = texN.sample(quad_sampler, inFrag.tex_coord);
}
return color; …我有一个非常慢的工作金属应用程序,需要运行得更快.我相信问题是我创建了太多的MTLCommandBuffer对象.
我创建这么多MTLCommandBuffer对象的原因是我需要向像素着色器发送不同的统一值.我粘贴了一些代码来说明下面的问题.
for (int obj_i = 0 ; obj_i < n ; ++obj_i)
{
// I create one render command buffer per object I draw so I can use different uniforms
id <MTLCommandBuffer> mtlCommandBuffer = [metal_info.g_commandQueue commandBuffer];
id <MTLRenderCommandEncoder> renderCommand = [mtlCommandBuffer renderCommandEncoderWithDescriptor:<#(MTLRenderPassDescriptor *)#>]
// glossing over details, but this call has per object specific data
memcpy([global_uniform_buffer contents], per_object_data, sizeof(per_data_object));
[renderCommand setVertexBuffer:object_vertices offset:0 atIndex:0];
// I am reusing a single buffer for all shader calls
// this is killing performance …