小编col*_*ass的帖子

我想设置反应路由器以用于子域.我不确定子域代理的逻辑应该在哪里.

我想要:

roxy.coolestblog.com/profile路由到coolestblog.com/roxy/profile mohammed.coolestblog.com/profile路由到coolestblog.com/mohammed/profile benben.coolestblog.com/profile路由到coolestblog.com/benben/profile

另一个用例:

en.coolestblog.com/some-article路由到coolestblog.com/en/some-article fr.coolestblog.com/un-article路由到coolestblog.com/fr/un-article es.coolestblog.com/una-article路由到coolestblog.com/es/una-article

我已经让它在没有子域的情况下工作了.

我怎样才能实现这一点,以便在客户端和服务器上都可以工作？

我正在为组件库创建文档.我想要1个html字符串,它可以生成页面上的组件和文档.

我想要的是:

是)我有的:

当我检查HTML时,我的按钮标签不存在.当我使用innerHTML时,它们被剥离了.

我的组件代码:

private flatButtons = `<div class="button-wrapper">
      <my-button [type]="'default'" [raised]="false">Default</my-button>
    </div>
    <div class="button-wrapper">
      <my-button [type]="'primary'" [raised]="false">Primary</my-button>
    </div>
    <div class="button-wrapper">
      <my-button [type]="'success'" [raised]="false">Success</my-button>
    </div>
    <div class="button-wrapper">
      <my-button [type]="'info'" [raised]="false">Info</my-button>
    </div>
    <div class="button-wrapper">
      <my-button [type]="'warning'" [raised]="false">Warning</my-button>
    </div>
    <div class="button-wrapper">
      <my-button [type]="'danger'" [raised]="false">Danger</my-button>
    </div>`

constructor() {}

getCode() {
    return html_beautify(this.flatButtons, this.options)
}

我的HTML模板:

<div class="row">
<div class="col-sm-6 col-xs-12">
  <mi-card title="Flat Buttons" baCardClass="with-scroll button-panel">
    <div id="flatButtons" [innerHTML]="getCode()">
    </div>
  </mi-card>
</div>
<div class="col-sm-6 col-xs-12">
  <pre>{{getCode()}}</pre>
</div>

我正在用纯C编写通用链表实现.

struct Node {
    void *value;
    struct Node *next;
};

struct LinkedList {
    struct Node *start;
    struct Node *end;
};

void LinkedList_new(struct LinkedList* llist) {
    llist->start = 0;
    llist->end = 0;
    return;
}

void addNode( struct LinkedList *ll, void *_value ) {
    if ( NULL == ll->start ) {
        ll->start = (struct Node *) malloc( sizeof(struct Node) );
        ll->end = ll->start;
    } else {
        ll->end->next = (struct Node *) malloc( sizeof(struct Node) );
        ll->end = ll->end->next;
    }
    ll->end->value = _value; …

我正在编写一个API的包装器.api使用基本身份验证,然后POST请求需要PostForm值.我正在做这样的事情:

func NewFoo(name string) string {
    client := &http.Client{}
    URL := HOST + "foo/"
    req, err := http.NewRequest("POST", URL, nil)
    v := url.Values{}
    v.Set("name", name)
    req.Form = v
    req.SetBasicAuth(EMAIL, PASSWORD)
    resp, err := client.Do(req)
    if err != nil {
        log.Fatal(err)
    }
    bodyText, err := ioutil.ReadAll(resp.Body)
    s := string(bodyText)
    return s
}

我有一个类似的,没有表单值的GET请求,它的工作原理.当我运行它时,它告诉我需要"名称"值.(所以它没有得到它)

有什么理由不起作用吗？

我在创建接口数组这个简单的任务时遇到了困难.这是我的代码,

var result float64
for i := 0; i < len(diff); i++ {
    result += diff[i]
}
result = 1 / (1 + math.Sqrt(result))

id1 := user1.UserId
id2 := user2.UserId

user1.Similar[id2] = [2]interface{id2, result}
user2.Similar[id1] = [2]interface{id1, result}

结果是一个浮点数,用户*.UserId是一个int.

我的错误信息是

syntax error: name list not allowed in interface type

我通过自制软件在我的Mac上下载了Rabbitmq。按照这些说明，我将sbin添加到path中，然后调用：

$ Rabbitmq服务器

并得到以下错误：

BOOT FAILED ===========

Error description:
   {error,
       {cannot_delete_plugins_expand_dir,
           ["/usr/local/var/lib/rabbitmq/mnesia/rabbit@localhost-plugins-expand",
            {cannot_delete,
                 "/usr/local/var/lib/rabbitmq/mnesia/rabbit@localhost-plugins-expand/amqp_client-3.3.2/ebin/amqp_auth_mechanisms.beam",
            eacces}]}}

Log files (may contain more information):
   /usr/local/var/log/rabbitmq/rabbit@localhost.log
   /usr/local/var/log/rabbitmq/rabbit@localhost-sasl.log

Stack trace:
   [{rabbit_plugins,prepare_plugins,3,
                  [{file,"src/rabbit_plugins.erl"},{line,123}]},
    {rabbit,'-boot/0-fun-1-',0,[{file,"src/rabbit.erl"},{line,332}]},
    {rabbit,start_it,1,[{file,"src/rabbit.erl"},{line,354}]},
    {init,start_it,1,[]},
    {init,start_em,1,[]}]

{"init terminating in do_boot",{rabbit,failure_during_boot,{error {cannot_delete_plugins_expand_dir,["/usr/local/var/lib/rabbitmq/mnesia/rabbit@localhost plugins-expand",{cannot_delete,"/usr/local/var/lib/rabbitmq/mnesia/rabbit@localhost-plugins-expand/amqp_client-3.3.2/ebin/amqp_auth_mechanisms.beam",eacces}]}}}}

Crash dump was written to: erl_crash.dump
init terminating in do_boot ()

有人遇到过此错误吗？

我的客户端javascript将此JSON发布到服务器端:

{ username: 'hello', password: 'world' }

我的Go服务器端代码:

type AuthJSON struct {
  Username    string `json:"username"`
  Password  string `json:"password"`
}

func AuthenticationHandler(w http.ResponseWriter, r *http.Request) {

   // Parse the incoming user/pass from the request body
   var body AuthJSON
   err := json.NewDecoder(r.Body).Decode(&body)
   log.Println(body)
   log.Println(body.Username)
   if err != nil {
      log.Println(err)
      panic(err)
   }
   ...
}

我的终端如下所示:

2013/07/31 20:26:53 { }
2013/07/31 20:26:53 
2013/07/31 20:26:53 invalid character 'u' looking for beginning of value
2013/07/31 20:26:53 http: panic serving [::1]:58141: invalid character 'u' looking for …

我有一个深层嵌套的结构,它包含两个切片,如下所示:

package main

import "fmt"

type bar struct {
    v1 []int
    v2 []int
}

type foo struct{ bar bar }
type tar struct{ foo foo }

func main() {
    f := &tar{foo: foo{bar: bar{v1: [2], v2: [3]}}}
    fmt.Printf("Hello, playground %s", f)
}

如何初始化两个切片？或者我如何使这个代码工作？

以下是Golang Play:http://play.golang.org/p/zLutROI4YH .

尝试在 go 中将 map[int] 解析为用户定义的结构：

这是数据模式。

type Recommendation struct {
    Book  int     `json:"book"`
    Score float64 `json:"score"`
}

这是 json 编组：

ureco := make(map[int]data.Recommendation)
ureco, _ = reco.UserRunner()

json, _ := json.Marshal(ureco)
fmt.Println(json)

其中 reco.UserRunner() 返回适当的结构类型。

这将打印一个空的 json 对象：

[]

更新：

错误信息：

json: unsupported type: map[int]data.Recommendation

那么我如何 json 结构映射？还是有替代方法？

我遇到的是节点:

var foo = bar || barfoofoo || foooobar;

我怎么能在go中实现这个.

我正在使用freewall.http://vnjs.net/www/project/freewall/

试图在freewall术语中获得0保证金或0"gutter".这是我的HTML

<div class="free_wall">  
    <div class="brick"></div>  
    <div class="brick"></div>  
    <div class="brick"></div>  
    <div class="brick"></div>  
    <div class="brick"></div>  
    <div class="brick"></div>
    <div class="brick"></div>  
    <div class="brick"></div> 
</div>

这是我的css:

.free_wall {
        width: 100%;
        margin: 0;
        padding: 0;
        display: block;
    }
    .brick {
       background: rgb(135, 199, 135);
       width: 320px;
       height: 320px;
       margin: 0;
       padding: 0;
    }

继承我的代码:

$(function() {
    var wall = new freewall(".free_wall");
    wall.fitZone();
    //wall.refresh();
    wall.reset({
        selector: '.brick',
        gutterY: 0,
        gutterX: 0,
    });
});

我无法链接我的CSS样式表:

层次:

index.html的:

// index.html
<!DOCTYPE html>
<html>
  <head>
    <link href="css/index.css" type="text/css" rel="stylesheet">
  </head>
  <body>
    <p class="blue">Hello</p>
  </body>
</html>

index.css:

// index.css
.blue {
  font:blue;
  font-size: 20px;
}