我正在使用Scala 2.10.3运行此程序:
object Test {
def main(args: Array[String]) {
def factorial(x: BigInt): BigInt =
if (x == 0) 1 else x * factorial(x - 1)
val N = 1000
val t = new Array[Long](N)
var r: BigInt = 0
for (i <- 0 until N) {
val t0 = System.nanoTime()
r = r + factorial(300)
t(i) = System.nanoTime()-t0
}
val ts = t.sortWith((x, y) => x < y)
for (i <- 0 to 10)
print(ts(i) + " ")
println("*** " …Run Code Online (Sandbox Code Playgroud) 我使用以下命令在 Windows 10 上安装 Dear ImGui:
vcpkg install imgui:x64-windows
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仅安装:
imgui[core]:x64-windows -> 1.85
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我怀疑我需要从此列表中添加一个或多个绑定:
imgui[allegro5-binding] Make available Allegro5 binding
imgui[docking-experimental] Build with docking support
imgui[dx10-binding] Make available DirectX10 binding
imgui[dx11-binding] Make available DirectX11 binding
imgui[dx12-binding] Make available DirectX12 binding
imgui[dx9-binding] Make available DirectX9 binding
imgui[freetype] Build font atlases using FreeType instead of stb_truetype
imgui[glfw-binding] Make available GLFW binding
imgui[glut-binding] Make available Glut binding
imgui[libigl-imgui] Install the libigl-imgui headers
imgui[marmalade-binding] Make available Marmalade binding
imgui[metal-binding] Make available Metal binding
imgui[opengl2-binding] Make …Run Code Online (Sandbox Code Playgroud) 我无法抽出时间添加功能.我正在使用Qt4.这是代码片段,它产生两个相同的时间而不是100个不同的时间.
void main()
{
QTextStream out (stdout);
QTime t = QTime::currentTime();
out << t.toString("hh:mm:ss") << " -> ";
t.addSecs(100);
out << t.toString("hh:mm:ss");
}
Run Code Online (Sandbox Code Playgroud) 在F#中有一个N个元素长列表,我想提取所有可能的M个元素长重叠的连续子列表(M <N),例如:
[1; 2; 3; 4; 5]
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产生
[[1; 2; 3]; [2; 3; 4]; [3; 4; 5]]
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对于M = 3.
我知道这样做的必要方法,但是有一个简洁的功能诀窍吗?
此代码段不能使用VS2013或ICC 16进行编译:
class C2;
class C1
{
public:
float x, y;
template<typename T>
C1 (T x, T y) : x(static_cast<float>(x)), y(static_cast<float>(y)) {};
C1 (const C2 &a, int i) : x(0), y(0) {};
};
void main()
{
C1 p(1.5, 2);
}
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因为没有C1构造函数的实例匹配参数列表(double, int),但是当我C2用PolyLine它替换它时会编译并1.5以某种方式转换为PolyLine.我在一个有很多依赖项的大型项目中测试它,所以我只能在这里放入标题的一个片段:
class PolyLine
{
protected:
enum {INIT_LENGTH = 16};
public:
typedef float (PolyLine::*Fit)(Point2D&, Point2D&, const int, const int, const float) const;
vector<float> x; ///< Vector with X …Run Code Online (Sandbox Code Playgroud) 有没有一个很好的理由为什么这个代码在没有警告的情况下编译(并在运行时崩溃)与Visual C++ 2010:
int a = *((int*)nullptr);
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静态分析应该得出结论它会崩溃,对吧?
有人可以解释为什么编译器给我这个错误
类型不匹配.期待'a [] - >字符串,
但给出'a [] - >'a []
类型'字符串'与类型''a []'不匹配
在此代码段上:
let rotate s: string =
[|for c in s -> c|]
|> Array.permute (function | 0 -> (s.Length-1) | i -> i-1)
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而下面的那个编译得很好:
let s = "string"
[|for c in s -> c|]
|> Array.permute (function | 0 -> (s.Length-1) | i -> i-1)
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f# ×2
benchmarking ×1
c++11 ×1
imgui ×1
list ×1
nullptr ×1
optimization ×1
qt ×1
qt4 ×1
scala ×1
visual-c++ ×1
windows ×1