我用:
我想检查我的占位符是否为空.
<div>
{% placeholder "my_placeholder" or %}
{% endplaceholder %}
</div>
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如果占位符为空,我不希望创建占位符之间的html.
{% if placeholder "my_placeholder" %}
<div>
{% placeholder "my_placeholder" or %}
{% endplaceholder %}
</div>
{% endif %}
Run Code Online (Sandbox Code Playgroud) 我无法在xmlrpclib.ServerProxy()上获得方法列表.我尝试过使用dir(); 但是,解释器会一直返回错误.
这是我试过的:
>>>s = xmlrpclib.ServerProxy("http://192.168.1.72:8888")
>>>dir(s)
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我收到这个错误:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/xmlrpclib.py", line 1224, in __call__
return self.__send(self.__name, args)
File "/usr/lib/python2.7/xmlrpclib.py", line 1578, in __request
verbose=self.__verbose
File "/usr/lib/python2.7/xmlrpclib.py", line 1264, in request
return self.single_request(host, handler, request_body, verbose)
File "/usr/lib/python2.7/xmlrpclib.py", line 1297, in single_request
return self.parse_response(response)
File "/usr/lib/python2.7/xmlrpclib.py", line 1473, in parse_response
return u.close()
File "/usr/lib/python2.7/xmlrpclib.py", line 793, in close
raise Fault(**self._stack[0])
xmlrpclib.Fault: <Fault 1: '<type \'exceptions.Exception\'>:method "__dir__" is not supported'>
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不支持Dir(),如何获取方法列表?
我在目录中有两个文件,它们都是.txt文件,每行有一个单词,用于多行.我需要将它们合并,然后将新文件按字母顺序排列.
我在PHP中完成了这个,但是我怎么能在Python 2.7中做到这一点?
<?php
$files = glob("./files/*.??");
$out = fopen("listTogether.txt", "w");
foreach($files as $file){
fwrite($out, file_get_contents($file));
}
fclose($out);
?>
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