我认为这是一个愚蠢的问题,但我无法在PHP上找到它.为什么在以下代码中带有=的+:
function calculateRanking()
{
$created = $this->getCreated();
$diff = $this->getTimeDifference($created, date('F d, Y h:i:s A'));
$time = $diff['days'] * 24;
$time += $diff['hours'];
$time += ($diff['minutes'] / 60);
$time += (($diff['seconds'] / 60)/60);
$base = $time + 2;
$this->ranking = ($this->points - 1) / pow($base, 1.5);
$this->save();
}
这是多少时间有所有这些值,或者更确切地说它是将所有值添加到$ time？
谢谢
我一直在寻找这个,我似乎只是遇到了相同的文章,在这段代码中:
try
{
//some code
}
catch(Exception $e){
throw $e;
}
$ e存储在哪里或网站管理员如何看待它？我应该寻找特殊功能吗？
在我的css文件中,我的页脚有以下样式:
#footer {
text-align: center;
font-size: .7em;
color:#000000;
}
这是页脚部分的html:
<div id="footer">
<br> //google ad
<br>
<br>
<A HREF="http://www.site1.com">Blog</A> <A
HREF="http://site1/rss.xml">RSS</A> <A
HREF="http://www.mexautos.com">Autos Usados</A> <A
HREF="http://www.site2">Videos Chistosos</A> <A
HREF="http:/s.blogspot.com">Fotos de Chavas</A><br>
Derechos Reservados © 2008-<?=date('Y')?> address<br>
</div>
但出于某种原因,一些链接显示有下划线.
任何想法我怎么能这样做链接不会出现下划线？
谢谢
我正在尝试建立一个可以投票的新闻链接的网站,我有以下代码:
case 'vote':
require_once('auth/auth.php');
if(Auth::isUserLoggedIn())
{
require_once('data/article.php');
require_once('includes/helpers.php');
$id = isset($_GET['param'])? $_GET['param'] : 0;
if($id > 0)
{
$article = Article::getById($id);
$article->vote();
$article->calculateRanking();
}
if(!isset($_SESSION)) session_start();
redirectTo($_SESSION['action'], $_SESSION['param']);
}
else
{
Auth::redirectToLogin();
}
break;
现在的问题是如何检查所以同一个用户不投票两次,这里是文章文件:
<?php
require_once($_SERVER['DOCUMENT_ROOT'].'/config.php');
require_once(SITE_ROOT.'includes/exceptions.php');
require_once(SITE_ROOT.'data/model.php');
require_once(SITE_ROOT.'data/comment.php');
class Article extends Model
{
private $id;
private $user_id;
private $url;
private $title;
private $description;
private $ranking;
private $points;
function __construct($title = ' ', $description = ' ', $url = ' ', $username = ' ', $created = ' ', …我有这门课:
.news_item_info
{
font-size: .7em;
color:#000000;
text-indent: 30px;
a:link { color: #000000; }
a:visited { color: #000000; }
}
这里有代码:
<div class="news_item_info">
<?php echo $articles[$index]->getPoints(); ?> puntos por <span class="news_item_user"><a href="/index.php?action=user¶m=<?php echo $articles[$index]->getUsername(); ?>">
<?php echo $articles[$index]->getUsername(); ?></a> </span>
<?php echo $articles[$index]->getElapsedDateTime(); ?> | <span class="comments_count"><a href="<?php echo "/index.php?action=comments¶m=".$articles[$index]->getId(); ?>"><?php echo $articles[$index]->getNumberOfComments($articles[$index]->getId()); ?> comentarios</a></span>
</div>
问题是,在我访问用户配置文件后,它显示为灰色,我想保持黑色.
如果有人知道答案我会很感激.
我有一个每天只有大约100人的网站但是当我以用户身份登录时收到此错误消息:
Warning: mysqli::mysqli() [mysqli.mysqli]: (42000/1203): User mexautos_Juan already has more than 'max_user_connections' active connections in /home/mexautos/public_html/kiubbo/data/model.php on line 26
Warning: mysqli::query() [mysqli.query]: Couldn't fetch mysqli in /home/mexautos/public_html/kiubbo/data/model.php on line 87
Query failed
我刷新页面几次,现在还可以,但是由于我没有那么多用户,我怀疑我的代码中出现了错误,我应该在哪里寻找它？
谢谢
编辑:这是模型文件:
<?php
/*
Model is the base class from which the other
model classes will be derived. It offers basic
functionality to access databases
*/
require_once($_SERVER['DOCUMENT_ROOT'].'/config.php');
require_once(SITE_ROOT.'includes/exceptions.php');
class Model {
private $created;
private $modified;
static function getConnection()
{
/*
Connect to the database and return a …我正在开发一个链接投票网站,我有这个功能,检查用户是否已经投票链接:
function has_voted($user)
{
try
{
$db = parent::getConnection();
$query = "select id from votes where username = '$user' and article_id = $this->id";
$results = parent::execSQL($query);
if($results->num_rows == 1) {
return true;
}
else
{
return false;
}
parent::closeConnection($db);
}
catch(Exception $e){
throw $e;
}
}
在首页我显示一个图像用这行投票:
<a href="/index.php?action=vote&param=<?php echo $articles[$index]->getId(); ?>">
<img class="vote_button" src="assets/images/triangulo.png" />
</a>
如果用户已经投票,我希望它插入"if"来显示不同的图像,我尝试了这个,但它显示错误:
<a href="/index.php?action=vote&param=<?php echo $articles[$index]->getId(); ?>">
<?php if($articles[$index]->has_voted($articles[$index]->getUsername()) == true)
{ ?><img src="assets/images/triangulo.png"/></a><?php }
else
{ ?><img class="vote_button" src="assets/images/triangulo2.png" /></a><?php } ?>
+++编辑: …
我有这个代码:
$query = "select id from votes where username = '$user' and article_id = $this->id";
我尝试使用此代码来清理它:
$query = sprintf("select id from votes where username = '$user' and article_id = $this->id",
mysql_real_escape_string($user),
mysql_real_escape_string($password));
但我得到mysql_real_escape行的这个错误:
Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'mexautos'@'localhost' (using password: NO) in /home/mexautos/public_html/kiubbo/data/article.php on line 145 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in /home/mexautos/public_html/kiubbo/data/article.php on line 145 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'mexautos'@'localhost' (using password: NO) in /home/mexautos/public_html/kiubbo/data/article.php on …