我正在尝试将查询从 Redshift 转换为 Snowflake SQL。
Redshift 查询如下所示:
SELECT
cr.creatives as creatives
, JSON_ARRAY_LENGTH(cr.creatives) as creatives_length
, JSON_EXTRACT_PATH_TEXT(JSON_EXTRACT_ARRAY_ELEMENT_TEXT (cr.creatives,0),'previewUrl') as preview_url
FROM campaign_revisions cr
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雪花查询如下所示:
SELECT
cr.creatives as creatives
, ARRAY_SIZE(TO_ARRAY(ARRAY_CONSTRUCT(cr.creatives))) as creatives_length
, PARSE_JSON(PARSE_JSON(cr.creatives)[0]):previewUrl as preview_url
FROM campaign_revisions cr
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似乎 JSON_EXTRACT_PATH_TEXT 未正确转换,因为 Snowflake 查询会导致错误:
解析 JSON 时出错:输入中有多个文档
cr.creatives 的格式如下:
"[{""previewUrl"":""https://someurl.com/preview1.png"",""device"":""desktop"",""splitId"":null,""splitType"":null},{""previewUrl"":""https://someurl.com/preview2.png"",""device"":""mobile"",""splitId"":null,""splitType"":null}]"
Run Code Online (Sandbox Code Playgroud) 有org.w3c.dom.Document中的方法,例如getElementById(String elementId),getElementsByTagName(String tagname)等等,但有可能获得通过他们的文本值的元素?