小编Jon*_*nas的帖子

我收到一个新错误:

Starting up
Exception in thread "main" java.lang.UnsatisfiedLinkError: no lwjgl in java.library.path
    at java.lang.ClassLoader.loadLibrary(ClassLoader.java:1734)
    at java.lang.Runtime.loadLibrary0(Runtime.java:823)
    at java.lang.System.loadLibrary(System.java:1028)
    at org.lwjgl.Sys$1.run(Sys.java:75)
    at java.security.AccessController.doPrivileged(Native Method)
    at org.lwjgl.Sys.doLoadLibrary(Sys.java:68)
    at org.lwjgl.Sys.loadLibrary(Sys.java:84)
    at org.lwjgl.Sys.<clinit>(Sys.java:101)
    at org.lwjgl.opengl.Display.<clinit>(Display.java:128)
    at org.newdawn.slick.AppGameContainer$1.run(AppGameContainer.java:39)
    at java.security.AccessController.doPrivileged(Native Method)
    at org.newdawn.slick.AppGameContainer.<clinit>(AppGameContainer.java:36)
at GameStarter$.main(SnakeGame.scala:43)
at GameStarter.main(SnakeGame.scala)

我导入了lwjgl.jar图书馆.

如何在Java中添加menuItem另一个的内部/子部分？menuItem是否可以 ？

我目前正在尝试将 next-auth 与 google 提供商一起使用，并将 prisma 与我的下一个 js 应用程序一起使用，但我收到此错误：

Detected default export in '/MyProject/foodbrain/app/api/auth/[...nextauth]/route.ts'. Export a named export for each HTTP method instead.

随着：

No HTTP methods exported in 'MyProject/foodbrain/app/api/auth/[...nextauth]/route.ts'. Export a named export for each HTTP method.

我的route.ts文件：

import { PrismaAdapter } from "@next-auth/prisma-adapter";
import { PrismaClient } from "@prisma/client";
import NextAuth from "next-auth";
import GoogleProvider from "next-auth/providers/google";

const prisma = new PrismaClient();

export default NextAuth({
  adapter: PrismaAdapter(prisma),
  providers: [
    GoogleProvider({
      clientId: process.env.GOOGLE_CLIENT_ID,
      clientSecret: process.env.GOOGLE_CLIENT_SECRET,
    }),
  ],
});

我在 …

questionArray.addObject("Hi honey, I just got to work. What are you upto?");
    answerArray.addObject("I was just thinking about you darling.:Just missing you from the time you left.:I was just going through our wedding photos.:Well right now, just talking to you & its giving me a headache.:Nothing much I was just texting my ex-boyfriend.");
    subQuestionArray.addObject("What do you mean by that?");
    subAnswerArray.addObject("Oh nothing dear, just missing you.:Nothing, just that I think dumping my ex was a mistake.");
    statementArray.addObject("Good to know, I've work to do, …

我想在 for 循环中使用 next() 来处理下面的单词，而不推进 for 循环。

words = ["please", "do", "loop", "in", "order"]
for word in words:
    print word
    checknextword = str(next((word for word in words), None))

因此，我想打印：

>>>please
>>>do
>>>loop
>>>in
>>>order

但代码产生：

>>>please
>>>loop
>>>order

我正在使用 exec 运行 Kubernetes 服务，它在 statefulset 中几乎没有 pod。如果我在 exec 中杀死服务使用的主 pod 之一，它会以代码 137 退出。我想在杀死后立即将其转发到另一个 pod 或在退出之前应用等待。我需要帮助。等待答复。谢谢你。