小编gui*_*ido的帖子

我想做这样的事情:

<jaxws:endpoint id="AbcEsbHTTPEndpoint" 
    implementor="com.abc.esb.ABCWSServiceImpl"
    address="/ABCWSServiceService"
    wsdlLocation="wsdl/ABCWSService.wsdl"
    endpointName="e:ABCWSService"
    serviceName="s:ABCWSServiceService"
    xmlns:e="http://com.abc.esb/abcesb/services/ABCWSService"
    xmlns:s="http://com.abc.esb/abcesb/services/ABCWSService">
</jaxws:endpoint>


<camelContext xmlns="http://camel.apache.org/schema/spring">
    <route>
        <from uri="cxf:bean://ABCWSServiceService"/>
        <to uri="cxf:bean:decodeClient"/>
    </route>
</camelContext>    

<jaxws:client id="decodeClient" 
    address="http://ESB-DEV1:9081/abcesb/services/Decoder"
    wsdlLocation="http://ESB-DEV1:9081/abcesb/services/Decoder?wsdl" 
    serviceClass="com.abc.esb.ABCServiceInterface" 
    abstract="true" > 
</jaxws:client>  

我不明白如何配置骆驼路由从<jaxws:endpoint>到<jaxws:client> 使用的语法是什么？我知道你可以使用<cxf:cxfEndpoint>但如果我不需要,我不想使用它.

我知道如何使用JBI执行此操作,但我想使用OSGI包而不是JBI将其部署到servicemix中.