小编Chu*_*cks的帖子

如何禁用文件的yum事务检查？

Transaction check error:
  file /usr/local/xenco/backend/current from install of xenco-rr-1.9.6-104.x86_64 conflicts with file from package xenco-server-1.9.6-104.x86_64

我正在尝试将范围转换为列表.

nums = []
for x in range (9000, 9004):
    nums.append(x)
    print nums

产量

[9000]
[9000, 9001]
[9000, 9001, 9002]
[9000, 9001, 9002, 9003]

我只需要类似的东西

 [9000, 9001, 9002, 9003]

我如何获得所需的列表？

for循环中的Python列表,如何在一个列表中包含所有内容

import os
dir="/tmp/logvol/logs/fil/sap/archive/"
n=os.listdir(dir)
#print n

for x in n:
 #print x
 l = [];
 l.append(os.path.join(dir,x))
 print l

输出:

['/tmp/logvol/logs/fil/sap/archive/m.log']
['/tmp/logvol/logs/fil/sap/archive/k.log']
['/tmp/logvol/logs/fil/sap/archive/j.log']
['/tmp/logvol/logs/fil/sap/archive/p.log']

我需要一个列表,而不是多个列表.

['/tmp/logvol/logs/fil/sap/archive/m.log', '/tmp/logvol/logs/fil/sap/archive/k.log', '/tmp/logvol/logs/fil/sap/archive/j.log', '/tmp/logvol/logs/fil/sap/archive/p.log']

伙计们 - 我有两个清单

list1=['a','b']
list2=['y','z']

我想将变量发送到如下函数:

 associate_address(list1[0],list2[0])
 associate_address(list1[1],list2[1])

我的剧本:

for l in list1:
 for i in list2:
  conn.associate_address(i,l)

我收到以下输出:

conn.associate_address(a,y)
conn.associate_address(a,z)

我希望它看起来像这样:

conn.associate_address(a,y)
conn.associate_address(b,z)