我想在我的webView中打开iTunes链接,但是当webView启动页面时,它会重定向到Safari浏览器.在那里,网址正在打开,但我希望它在我的webView中打开.
- (void)viewDidLoad {
NSString *urlAddress = @"http://itunes.apple.com/us/app/foodcheck-traffic-light-nutrition/id386368933?mt=8";
//Create a URL object.
NSURL *url = [NSURL URLWithString:urlAddress];
//URL Requst Object
NSURLRequest *requestObj = [NSURLRequest requestWithURL:url];
//Load the request in the UIWebView.
[webView loadRequest:requestObj];
[super viewDidLoad];
}
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请建议一种解决此问题的方法.
所以我有一个编辑页面上有可编辑字段的对接...简单更新
@patient.update_attributes(params[:patient])......一切都很棒,除了....
我在这20个中有一个字段,我需要在它准备好db之前稍微调整一下,看起来我要么做
两次旅行
@patient.update_attributes(params[:patient])
@patient.update_attribute( :field=>'blah')
或者单独设置它们
patient.update_attributes(:field1=>'asdf', :field2=>'sdfg',:field3=>'dfgh', etc...)
我错过了这样做的方法吗?
继承我的代码:
import hashlib
real = hashlib.sha512("mom")
status = True
while status:
inp = raw_input("What's the password?")
converted = hashlib.sha512(inp)
if converted == real:
print "Access granted!"
status = False
else:
print "Access denied."
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我是hashlib的新手,我只是在玩它.我认为这样做会验证用户输入实际密码的哈希值,但是如果输入正确的密码,它仍会出现"访问被拒绝".谁能指出我正确的方向?
我正在开发一个计算用户行进距离的应用程序.我正在使用CLLocationManager类来执行此操作,但我最初获取缓存数据,并且距离变量也以突然的速率增加.请帮帮我...我用过以下代码....
注意:距离是静态变量.这里
- (void)viewDidLoad {
[super viewDidLoad];
//bestEffortAtLocation = nil;
oldLocat = [[CLLocation alloc]init];
newLocat = [[CLLocation alloc]init];
locationManager =[[CLLocationManager alloc]init];
locationManager.delegate = self;
locationManager.distanceFilter = kCLDistanceFilterNone;
locationManager.desiredAccuracy = kCLLocationAccuracyBest;
[locationManager startUpdatingLocation];
}
- (void)locationManager:(CLLocationManager *)manager
didUpdateToLocation:(CLLocation *)newLocation
fromLocation:(CLLocation *)oldLocation{
// test that the horizontal accuracy does not indicate an invalid measurement
if (newLocation.horizontalAccuracy < 0) return;
NSLog(@"accuracy %d",newLocation.horizontalAccuracy);
// test the age of the location measurement to determine if the measurement is cached
// in most cases you will …Run Code Online (Sandbox Code Playgroud) 我使用这个PHP 库进行 IMAP 连接。
如何使用 IMAP 获取邮箱的完整大小?
我尝试了这个工作代码,但它只返回收件箱目录的大小:
var_dump($imap->getMailboxStatistics());
Run Code Online (Sandbox Code Playgroud) 我收到此错误:
错误:在'CLLocation'之前预期')'
使用此代码:
@protocol MyCLControllerDelegate <NSObject>
@required
- (void)locationUpdate:(CLLocation *)location;
- (void)locationError:(NSError *)error;
@end
@interface MyCLController : NSObject <CLLocationManagerDelegate> {
CLLocationManager *locationManager;
id delegate;
}
@property (nonatomic, retain) CLLocationManager *locationManager;
@property (nonatomic, assign) id <MyCLControllerDelegate> delegate;
- (void)locationManager:(CLLocationManager *)manager
didUpdateToLocation:(CLLocation *)newLocation
fromLocation:(CLLocation *)oldLocation;
- (void)locationManager:(CLLocationManager *)manager
didFailWithError:(NSError *)error;
@end
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代码,我认为很好,我认为问题是库,但我之前添加了框架但不起作用.
可能是什么问题?