小编Nav*_*dse的帖子

我希望我的JSON看起来像这样:

{
    "information": [{
        "timestamp": "xxxx",
        "feature": "xxxx",
        "ean": 1234,
        "data": "xxxx"
    }, {
        "timestamp": "yyy",
        "feature": "yyy",
        "ean": 12345,
        "data": "yyy"
    }]
}

代码到目前为止:

import java.util.List;

public class ValueData {

    private List<ValueItems> information;

    public ValueData(){

    }

    public List<ValueItems> getInformation() {
        return information;
    }

    public void setInformation(List<ValueItems> information) {
        this.information = information;
    }

    @Override
    public String toString() {
        return String.format("{information:%s}", information);
    }

}

和

public class ValueItems {

    private String timestamp;
    private String feature;
    private int ean;
    private String data; …

当我使用JAVA时,我的页面跳转有问题,如果我使用:

response.sendRedirect("login.jsp")

然后我得到这个网址: http://localhost:8080/login.jsp

但是,如果我使用

request.getRequestDispathcer("login.jsp").forward(request, response)

然后我得到这个网址:( http://localhost:8080/Shopping/login.jsp"购物"是我模块的名称).

有什么不同？

如何使用JavaScript获取JSON对象中的键值和对象的长度.
例如:

[
  {
    "amount": " 12185",
    "job": "GAPA",
    "month": "JANUARY",
    "year": "2010"
  },
  {
    "amount": "147421",
    "job": "GAPA",
    "month": "MAY",
    "year": "2010"
  },
  {
    "amount": "2347",
    "job": "GAPA",
    "month": "AUGUST",
    "year": "2010"
  }
]

这里,这个数组的长度是3.为了获得值很好([0].amount),在索引中[0]它有3个名称值对.
所以,我需要得到这个名字(比如数量或工作......总共有四个名字),还要算出有多少名字？

我正在开发一个j2ee应用程序.在我的应用程序中,我有一个下拉列表(或选择元素).我想用JSON数据填充这个下拉列表作为Ajax响应.

以下是我的代码:

服务器端代码(json_source.java),它生成JSON响应.:

package demo.model;

import java.io.IOException;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.Statement;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import com.google.gson.*;

/**
 * Servlet implementation class json_source
 */
public class json_source extends HttpServlet {
private static final long serialVersionUID = 1L;


/**
 * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
 */
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException 
{
    JsonArray data_json=new JsonArray();

    Statement st_loginId=null;
    ResultSet rs_loginId=null;
    try
    {
        Connection con=null;

        Class.forName("oracle.jdbc.OracleDriver");

        /* Connection String for "OPERWH"(exadata) …

我正在创建并解雇NSTimer:

ncTimer = [NSTimer scheduledTimerWithTimeInterval:1.0
                                           target:self
                                         selector:@selector(handleTimer:)
                                         userInfo:nil
                                          repeats:YES];
[ncTimer fire];

和

- (void)handleTimer:(NSTimer *)chkTimer {
    // do stuff
}

我保留我的计时器:

@property (nonatomic, retain) NSTimer *ncTimer;

由于某种原因,计时器不重复.它只发射一次而不是再发射一次.

FHSTwitterEngine *engine = [FHSTwitterEngine sharedEngine];
[engine clearAccessToken];

我试过上面的代码但是当我再次尝试登录时,textfields没有presentModalViewController显示,它显示了授权应用程序按钮.

还有另一种方法, [engine clearConsumer];这导致Select and Copy the PIN在presentModalViewController

我正在Eclipse中使用maven项目为sonarqube创建一个新的语言插件,并在构建项目时面临以下错误:

Failed to execute goal com.mycila.maven-license-plugin:maven-license-plugin:1.9.0:
check (enforce-license-headers) on project sonar-java-plugin:
Some files do not have the expected license header -> [Help 1]

我有一个安静的Web服务,响应是:

{
    "cities": [{
        "id": "1",
        "name": "City 01",
        "state": "A1"
    }, {
        "id": "2",
        "name": "City 02",
        "state": "A1"
    }]
}

但我想要这个:

{
    [{
        "id": "1",
        "name": "City 01",
        "state": "A1"
    }, {
        "id": "2",
        "name": "City 02",
        "state": "A1"
    }]
}

我如何配置JAX-RS只使用JAX-RS功能而不是根节点生成JSON,而不是实现特定功能？我的代码需要可以在任何appserver上移植.

我正在尝试3.0的android操作栏,我参考

http://www.youtube.com/watch?v=gMu8XhxUBl8

代码TabsActivity如下:

package com.test.actionbar;

import android.app.ActionBar;
import android.app.ActionBar.Tab;
import android.app.Activity;
import android.app.Fragment; 
import android.app.FragmentTransaction;
import android.os.Bundle;

public class TabsActivity extends Activity{

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    ActionBar bar = getActionBar();
    bar.setNavigationMode(ActionBar.NAVIGATION_MODE_TABS);
    ActionBar.Tab tabA = bar.newTab().setText("A Tab");
    ActionBar.Tab tabB = bar.newTab().setText("B Tab");
    ActionBar.Tab tabC = bar.newTab().setText("C Tab");

    Fragment fragmentA = new AFragmentTab();
    Fragment fragmentB = new BFragmentTab();
    Fragment fragmentC = new CFragmentTab();

    tabA.setTabListener(new MyTabsListener(fragmentA));
    tabB.setTabListener(new MyTabsListener(fragmentB));
    tabC.setTabListener(new MyTabsListener(fragmentC));

    bar.addTab(tabA);
    bar.addTab(tabB);
    bar.addTab(tabC);

}

protected class MyTabsListener implements …

我有以下格式的JSON,我正在尝试写入CSV:

{
    "results": [{

            "geo_position": {
                "Field1": 11,
                "Filed2": 12
            },
            "Field3": 13,
            "Filed4": 14,
            "Field5": 15
        },

        {
            "geo_position": {
                "Field1": 21,
                "Filed2": 22
            },
            "Field3": 23,
            "Filed4": 24,
            "Filed5": 25
        }
    ]
}

我期待输出像:

field1,field2,field3,field4,field5
11,12,13,14,15
21,22,23,24,25

我得到输出CSV如下:

    geo_position,field3,field4,field5
   {Field1:11,Field2:12}, 13,14,15
   {Field2:21,Field2:22},23,24,25

我的java代码:

JSONObject jsonObj = new JSONObject(jsonArray);
System.out.println(jsonObj);
JSONArray docs = jsonObj.getJSONArray("results");
File file=new File("C:/fromJSON2.csv");
String csv = CDL.toString(docs);
FileUtils.writeStringToFile(file, csv);

有人可以帮我弄清楚为什么我会采用不同的格式.我应该怎么做以达到我期望的格式？