我传递了2个数组到我的视图.我希望我的嵌套循环只显示它的parent_id值与parent.id匹配的位置.例如.
arr1 = {"0":{"id":326,"parent_id":0,"title":"Mellow Mushroom voucher","full_name":"Patrick","message":"The voucher says $10 Voucher; some wording on the printout says, \"This voucher is valid for $20 Pizza\" but my purchase price or amount paid also says $20. Shouldn't that be $10","type":"Deals"}};
arr2 = {"0":{"id":327,"parent_id":326,"title":"Re: Mellow Mushroom voucher","full_name":"Patrick Williams","message":"Some message here","type":null};
...
<div data-ng-repeat = "parent in arr1">
<span>{{parent.title}}<span>
<div data-ng-repeat="child in arr2 | only-show-where-child.parent_id == parent.id">
<li>{{child.body}}</li>
</div>
</div>
这是角度中的可能/最佳实践吗？我应该在将节点传递给角度之前过滤节点中的对象吗？谢谢!