我在NDK中成功构建了HelloWorld示例.
我想建立库re-0.4.2,rim和baresip.
项目结构如图所示

如何构建上面的lib?
提前致谢.
我有一个Tornado应用程序,有时会有人添加一个阻止不适当时间的代码.
如何检测这些函数,甚至可以记录哪个处理程序/协同程序方法阻塞的时间比50毫秒长?
我在看_make_coroutine_wrapper()的tornado.gen,看不到的方式,来削减除了修改源-这是确定的一次性调试,但有没有更好的办法?
我试图在java中阅读RSS feed我正在使用ROME来读取feed,但是获取错误无法访问未找到org.jdom.Document的org.jdom.Document类文件SyndFeed feed = new SyndFeedInput().build(reader ); 1错误
我已将jdom添加到lib但仍然收到错误.请指导我如何解决它.我的代码如下
import java.net.URL;
import java.util.Iterator;
import com.sun.syndication.feed.synd.SyndEntry;
import com.sun.syndication.feed.synd.SyndFeed;
import com.sun.syndication.io.SyndFeedInput;
import com.sun.syndication.io.XmlReader;
public class Reader {
public static void main(String[] args) throws Exception {
URL url = new URL("http://viralpatel.net/blogs/feed");
XmlReader reader = null;
try {
reader = new XmlReader(url);
SyndFeed feed = new SyndFeedInput().build(reader);
System.out.println("Feed Title: "+ feed.getAuthor());
for (Iterator i = feed.getEntries().iterator(); i.hasNext();) {
SyndEntry entry = (SyndEntry) i.next();
System.out.println(entry.getTitle());
}
} finally {
if (reader != null)
reader.close();
} …Run Code Online (Sandbox Code Playgroud) 我有这个Grails的2.0.3项目,其中有两个型号DomainA和DomainB无一不是由相互关联的many-to-many关系,其中DomainB的一个孩子DomainA.
class DomainA {
// properties
static hasMany = [domains: DomainB]
}
class DomainB {
// properties
static hasMany = [domains: DomainA]
static belongsTo = [DomainA]
}
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鉴于这种设计,我想查询所有DomainB其中存在DomainA以下查询集的实例DomainA.
def domainsList = DomainA.createCriteria().list() {
// other criterions for the other properties
}
DomainB.createCriteria().list() {
inList("domains", domainsList)
// other criterions for the other properties
}
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执行上面的代码时,会出现错误提示,ERROR util.JDBCExceptionReporter - Parameter #1 has not been …
我知道有很多关于从java执行进程的问题.但是我无法使用提供的答案来解决我的问题.我正在尝试从java应用程序创建postgresql数据库备份.我使用以下代码
//ProcessBuilder probuilder = new ProcessBuilder(new String[]{"cmd","/c","D:/PostgreSQL 8.2/bin/pg_dump.exe","-U","usr","-i","-h","localhost","-p","5432","-F","c","-b","-f","D:/backup test/backups/test_27-1-2013_210.backup", "test"});
//ProcessBuilder probuilder = new ProcessBuilder(new String[]{"cmd","/c","D:\\PostgreSQL 8.2\\bin\\pg_dump.exe","-U","usr","-i","-h","localhost","-p","5432","-F","c","-b","-f","D:\\backup test\\backups\\test_27-1-2013_210.backup", "test"});
ProcessBuilder probuilder = new ProcessBuilder(new String[]{"cmd","/c","\"D:\\PostgreSQL 8.2\\bin\\pg_dump.exe\"","-U","usr","-i","-h","localhost","-p","5432","-F","c","-b","-f","\"D:\\backup test\\backups\\test_27-1-2013_210.backup\"", "test"});
Map<String, String> env = probuilder.environment();
env.put("PGPASSWORD", "mypass");
final Process process = probuilder.start();
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执行上面的代码后,我得到以下错误:
D:\PostgreSQL' is not recognized as an internal or external command,
operable program or batch file.
仅当备份文件的路径包含空格时才会出现问题,否则将创建备份.我试图在文件路径中使用斜杠和反斜杠,我引用文件路径,但每次都得到相同的错误.可以从命令提示符执行命令.
我做错了什么.ProcessBuilder中有关空格的参数数量是否有一些限制.谢谢
我在Makefile中有5个标签:
all: label1 label2 label3 label4 last_label
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我想last_label最后完成,我想用make -j.如果我使用.NOTPARALLEL,它将使所有这些NOTPARALLEL,任何关于如何做到这一点的建议?
我正在编写一个简单的构建器。我想有一个建设者方法消耗self,同时也消耗Vec<Node>并追加到一个Vec<Node>是self已经拥有。
我有这个方法:
pub fn with_nodes(mut self, mut nodes: Vec<Node>) -> Graph {
self.nodes.append(&nodes);
self
}
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nodes是一个非引用,因为我想使用它,这是mut因为Vec<>::append()它的参数发生了变异。
问题是,我得到:
46 | self.nodes.append(&nodes);
| ^^^^^^ types differ in mutability
|
= note: expected mutable reference `&mut Vec<Node>`
found reference `&Vec<Node>`
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为什么它nodes是不可变的,因为它被明确标记mut?我还能如何使参数成为局部可变的Vec?
我正在阅读Beej的" 网络编程指南 ".
在他的一个介绍示例中,他谈到了获取主机名的IP地址(例如google.com或yahoo.com).这是代码.
/*
** showip.c -- show IP addresses for a host given on the command line
*/
#include <stdio.h>
#include <string.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netdb.h>
#include <arpa/inet.h>
int main(int argc, char *argv[])
{
struct addrinfo hints, *res, *p;
int status;
char ipstr[INET6_ADDRSTRLEN];
if (argc != 2) {
fprintf(stderr,"usage: showip hostname\n");
return 1;
}
memset(&hints, 0, sizeof hints);
hints.ai_family = AF_UNSPEC; // AF_INET or AF_INET6 to force version
hints.ai_socktype = SOCK_STREAM;
if ((status = getaddrinfo(argv[1], NULL, …Run Code Online (Sandbox Code Playgroud) 我有一个域类,其中包含一个包含HTML代码的字符串变量.我想在myxml.gsp上显示此代码.
为此我写了以下代码:
Learn.groovy
public class Learn {
String content = ("<html><head><title>Learning Grails</title>
<body>Grails is fun</body></html>");
}
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myxml.gsp
<html>
<head>
<title>Xml Output</title>
</head>
<body>
<p>${learn.content}<p>
</body>
</html>
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然而,它无法获取"内容"的值,得到错误:"Cannot get property 'content' on null object".我做错了什么?有没有更好的方法来实现这一目标?