小编Tur*_*dfa的帖子

托管bean和弹簧控制器之间有什么区别?

我正在开发spring-hibernate-jsf应用程序,但我不理解managedbean和spring控制器之间的区别.我认为管理员就像控制器一样工作.使用controller或managedbean有什么好处吗?

java jsf spring controller javabeans

6
推荐指数
1
解决办法
8250
查看次数

Spring security redirection after login

After successfull login, it doesn't redirects to "index.php". It redirects same page which is "login.php". Is there something wrong with my spring-security.xml page?

顺便说一下,当我运行应用程序时,它会将我重定向到"login.php",这很好.但它没有显示primefaces组件,但显示html组件.在我成功登录后,它重定向同一页面,但这次它显示的是Primefaces组件而不是html组件.

<beans:beans xmlns="http://www.springframework.org/schema/security"
         xmlns:beans="http://www.springframework.org/schema/beans" 
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">

<http auto-config="true" use-expressions="true">
    <intercept-url pattern="/pages/login.xhtml*" access="permitAll"/>
    <intercept-url pattern="/**" access="hasRole('admin')" />
    <form-login login-page='/pages/login.xhtml' default-target-url="/pages/index.xhtml"                    
                authentication-failure-url="/pages/login.xhtml"/>
    <logout logout-success-url="/pages/logout.xhtml" />

</http>
<!--Authentication Manager Details -->    
<authentication-manager alias="authenticationManager">
    <authentication-provider user-service-ref="customUserDetailsService">
<!--            <password-encoder hash="md5"/>-->
    </authentication-provider>
</authentication-manager>
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我的web.xml

<welcome-file-list>
    <welcome-file>pages/index.xhtml</welcome-file>
</welcome-file-list>
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我的登录页面

<p:outputPanel id="loginOutputPanelId" style="border: navy">
                        <p:panelGrid id="loginInformationPanel" columns="2">
                            <h:outputText value="Username: "/>
                            <p:inputText value="#{loginController.userName}"/> …
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spring spring-security

6
推荐指数
1
解决办法
3万
查看次数

在spring-hibernate-maven项目中出错

我尝试运行项目时收到"class file functionContext not found"错误.它运行没有错误,但在我写了一些单元测试并删除它后它开始给出这个错误.这是错误堆栈跟踪;

编译错误:

Failure executing javac, but could not parse the error:


An annotation processor threw an uncaught exception.
Consult the following stack trace for details.
java.lang.RuntimeException: com.sun.tools.javac.code.Symbol$CompletionFailure: class file for org.jaxen.FunctionContext not found
    at org.eclipse.persistence.internal.jpa.modelgen.CanonicalModelProcessor.process(CanonicalModelProcessor.java:407)
    at com.sun.tools.javac.processing.JavacProcessingEnvironment.callProcessor(JavacProcessingEnvironment.java:793)
    at com.sun.tools.javac.processing.JavacProcessingEnvironment.discoverAndRunProcs(JavacProcessingEnvironment.java:722)
    at com.sun.tools.javac.processing.JavacProcessingEnvironment.access$1700(JavacProcessingEnvironment.java:97)
    at com.sun.tools.javac.processing.JavacProcessingEnvironment$Round.run(JavacProcessingEnvironment.java:1029)
    at com.sun.tools.javac.processing.JavacProcessingEnvironment.doProcessing(JavacProcessingEnvironment.java:1163)
    at com.sun.tools.javac.main.JavaCompiler.processAnnotations(JavaCompiler.java:1108)
    at com.sun.tools.javac.main.JavaCompiler.compile(JavaCompiler.java:824)
    at com.sun.tools.javac.main.Main.compile(Main.java:439)
    at com.sun.tools.javac.main.Main.compile(Main.java:353)
    at com.sun.tools.javac.main.Main.compile(Main.java:342)
    at com.sun.tools.javac.main.Main.compile(Main.java:333)
    at com.sun.tools.javac.Main.compile(Main.java:94)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:601)
    at org.codehaus.plexus.compiler.javac.JavacCompiler.compileInProcess(JavacCompiler.java:554)
    at org.codehaus.plexus.compiler.javac.JavacCompiler.compile(JavacCompiler.java:161)
    at org.apache.maven.plugin.AbstractCompilerMojo.execute(AbstractCompilerMojo.java:605)
    at org.apache.maven.plugin.CompilerMojo.execute(CompilerMojo.java:128) …
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spring annotations hibernate maven

5
推荐指数
3
解决办法
1万
查看次数

如何将双击侦听器添加到primefaces数据表

我想做的是; 当用户点击行时,它将选择行.当用户双击行时,它将开始单元格编辑.在Primefaces展示(http://www.primefaces.org/showcase/ui/d ... nstant.jsf),它说"即时行选择,dblclick选择和取消选择是使用ajax行为实现的." 但我无法找到他们实施dblclick选择的地方.有没有办法用双击事件启动单元格编辑事件?

jsf primefaces jsf-2

5
推荐指数
3
解决办法
3万
查看次数

出现后,primefaces对话框消失

我有一个commandButton和一个对话框.问题出现在对话框出现后,它会消失(1-2毫秒后).我的命令按钮或其对话框问题有问题吗?

<p:commandButton id="showDetailsButton"
     title="Details"
     onclick="details.show();"
     process="@this"
     update=":tabView:myForm:myDialogId"                                         
     icon="ui-icon-search">                          
</p:commandButton>


<p:dialog id="myDialogId"
      header="Details"
      widgetVar="details"
      resizable="false"
      height="600"
      width="450"                  
      >
//some stuff
</p:dialog>
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jsf primefaces jsf-2

5
推荐指数
2
解决办法
5838
查看次数

primefaces延迟加载未实现

我收到"java.lang.UnsupportedOperationException:未实现延迟加载." 错误.当我对项目进行debub时,lazyModel的构造函数正在运行,但是不执行load方法.

我的xhtml页面;

<p:dataTable id="envelopelistid" var="envelope"
                     value="#{incomingEnvelopeListController.lazyEnvelopeDataModel}"
                     selection="#{incomingEnvelopeListController.selectedEnvelope}" selectionMode="single"
                     rowKey="#{envelope.instanceIdentifier}"
                     sortMode="multiple"
                     lazy="true"
                     style="min-height: 300px"
                     paginator="true"
                     paginatorTemplate="{RowsPerPageDropdown} {FirstPageLink} {PreviousPageLink} {CurrentPageReport} {NextPageLink} {LastPageLink}"
                     rowsPerPageTemplate="5,10,15"
                     rows="10">
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我的控制员;

private LazyDataModel<Envelope> lazyEnvelopeDataModel;

public void init(){
...
lazyEnvelopeDataModel = new LazyEnvelopeDataModel(genericService,envelope);
}
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我懒惰的数据模型;

@Override
public List<Envelope> load(int first, int pageSize, String sortField, SortOrder sortOrder, Map<String, String> filters) {

    if (sortField == null) {
        sortField = "identificationId";
    }

    datasource = genericService.getByTemplate(envelopeModel, first, pageSize, new Order(sortField, Order.convertSortOrder(sortOrder.toString())));
    setRowCount((int) genericService.getCountByTemplate(envelopeModel));
    return datasource;


}
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jsf primefaces jsf-2

4
推荐指数
1
解决办法
6808
查看次数

如何创建一个高效的Spring-Hibernate项目结构?

我对服务有点困惑.为什么我必须使用服务进行hibernate集成?我想我可以直接使用DAO接口.例如,在本教程http://www.onlinetechvision.com/?p=566为什么他使用IUserService而不是IUserDAO.IUserService真的有必要吗?

spring hibernate spring-mvc

3
推荐指数
1
解决办法
447
查看次数

Primefaces数据表标题对齐

我有关于primefaces数据表的问题.如您所见,列边框和标题存在对齐问题.这是一个主要的错误或我的数据表有什么问题?顺便说一句,数据表有动态列.数据表

<p:dataTable     scrollable="true" scrollWidth="100%" editable="true" editMode="cell"   
var="invoiceLine" value="#{myController.invoiceLines}"                          
                         selection="#{myController.selectedInvoiceLine}" selectionMode="single" rowKey="#{invoiceLine.uuid}"
                         >
<p:columns value="#{myController.columns}" var="column"
                           styleClass="ui-editable-column" width="50"
                           columnIndexVar="colIndex">

//some stuff
</p:columns>         

            </p:dataTable>
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jsf primefaces jsf-2

3
推荐指数
2
解决办法
2万
查看次数

Spring安全性如何定义自定义角色名称

我找到了一些解决方案,但没有一个能为我工作.下面的代码给出

"Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Unsupported configuration attributes: [admin]" 
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错误.当我将auto-config属性更改为"true"时,再次给出相同的错误.

<http auto-config="false">
    <intercept-url pattern="/pages/login.xhtml*" access="IS_AUTHENTICATED_ANONYMOUSLY"/>
    <intercept-url pattern="/**" access="admin" />
    <form-login login-page='/pages/login.xhtml' default-target-url="/**"
                authentication-failure-url="/pages/login.xhtml"/>
    <logout logout-success-url="/pages/logout.xhtml" />
</http>

<beans:bean id="roleVoter" class="org.springframework.security.access.vote.RoleVoter">
    <beans:property name="rolePrefix" value=""/>
</beans:bean>
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spring spring-security

1
推荐指数
1
解决办法
3737
查看次数