当我在Martin Odersky的Scala编程中尝试抽象类型的Animal/Food示例时,
class Food
abstract class Animal {
type SuitableFood <: Food
def eat(food:SuitableFood)
}
class Grass extends Food
class Cow extends Animal {
type SuitableFood=Grass
override def eat(food:SuitableFood) {}
}
val bessy:Animal = new Cow
bessy.eat(new Grass)
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我收到以下错误:
scala> <console>:13: error: type mismatch;
found : Grass
required: bessy.SuitableFood
bessy.eat(new Grass)
^
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马丁的原始例子bessy.eat(new Fish)肯定会失败,但我没想到它也会失败Grass.可以通过让被避免上述错误bessy是Cow代替Animal:val bessy:Cow = new Cow.
这是否意味着动态绑定在这里不起作用?
编辑: Scala中常规继承的简单动态绑定:
abstract class Parent {
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