我有Ussntu 12.04和cassandra 1.1.3(tarball安装),当我尝试启动cassandra时,我得到以下内容:
user@ubuntu:~/apache-cassandra-1.1.3/bin$ sudo ./cassandra -f
xss = -ea -javaagent:./../lib/jamm-0.2.5.jar -XX:+UseThreadPriorities -XX:ThreadPriorityPolicy=42 -Xms4G -Xmx4G -Xmn800M -XX: +HeapDumpOnOutOfMemoryError -Xss128k
user@ubuntu:~/apache-cassandra-1.1.3/bin$
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根据cassandra文档,输出看起来不像预期的那样:
The service should start in the foreground and log gratuitously to
standard-out. Assuming you don't see messages with scary words like
"error", or "fatal", or anything that looks like a Java stack trace,
then chances are you've succeeded.
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那么,问题是什么?
我在以下代码中注意到以下行为(使用threading.Timer类):
import threading
def ontimer():
print threading.current_thread()
def main():
timer = threading.Timer(2, ontimer)
timer.start()
print threading.current_thread()
timer.cancel()
if timer.isAlive():
print "Timer is still alive"
if timer.finished:
print "Timer is finished"
if __name__ == "__main__":
main()
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代码的输出是:
<_MainThread(MainThread, started 5836)>
Timer is still alive
Timer is finished
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正如我们从输出中注意到的那样,计时器对象仍处于活动状态并在同一时间内完成.
事实上,我想将相似的功能称为数百次,我想知道那些"活着"的定时器是否会影响性能.
我想以适当的方式停止或取消计时器对象.我做得对吗?
谢谢
我想使用lxml解析HTML文档.我正在使用python 3.2.3和lxml 2.3.4(http://www.lfd.uci.edu/~gohlke/pythonlibs/#lxml)
我正在使用etree.iterparse解析文档,但它返回以下运行时错误:
Traceback (most recent call last):
File "D:\Eclipse Projects\Python workspace\Crawler\crawler.py", line 12, in <module>
for event, elements in etree.iterparse(some_file_like):
File "iterparse.pxi", line 491, in lxml.etree.iterparse.__next__ (src/lxml\lxml.etree.c:98565)
File "iterparse.pxi", line 512, in lxml.etree.iterparse._read_more_events (src/lxml\lxml.etree.c:98768)
TypeError: reading file objects must return plain strings
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问题是:如何解决这个运行时错误?
非常感谢你.
这是代码:
from io import StringIO
from lxml import etree
some_file_like = StringIO("<root><a>data</a></root>")
for event, elements in etree.iterparse(some_file_like): #<-- Run-time error happens here
print("%s, %4s, %s" % (event, elements.tag, elements.text))
Run Code Online (Sandbox Code Playgroud) 我正在构建一个具有以下特征的数据库:
我正在考虑按比例建造的Cassandra.
我的问题是:
编辑
我想确保我的观点是正确的.所以,下面的例子说明了我从你的答案得到的:
所以,如果我们有以下列系列(它包含一些商店产品及其详细信息)
products // column-family name
{
x = { "id":"x", // this is unique id for the row.
"name":"Laptop",
"screen":"15 inch",
"OS":"Windows"}
y = { "id":"y", // this is unique id for the row.
"name":"Laptop",
"screen":"17 inch"}
z = { "id":"z", // this is unique id for the row.
"name":"Printer",
"page per minute":"20 pages"}
}
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并且,我们要添加"name"搜索参数,我们将使用不同的行键创建另一个CF副本,如下所示:
products
{
"x:name:Laptop" = { "id":"x",
"name":"Laptop",
"screen":"15 inch",
"OS":"Windows"}
"y:name:Laptop" = …Run Code Online (Sandbox Code Playgroud) 我正在尝试在Python 2.7中创建一个具有以下要求的程序:
os.open(filepath, os.O_RDWR)我目前的算法是:
该方法具有以下缺点:
我应该怎么做才能满足上述要求的程序?
这是我目前的代码:
def is_video_file(filename):
video_file_extensions = (
'.264', '.3g2', '.3gp', '.3gp2', '.3gpp', '.3gpp2', '.3mm', '.3p2', '.60d', '.787', '.89', '.aaf', '.aec', '.aep', '.aepx',
'.aet', '.aetx', '.ajp', '.ale', '.am', '.amc', '.amv', '.amx', '.anim', '.aqt', '.arcut', '.arf', '.asf', '.asx', '.avb',
'.avc', '.avd', '.avi', '.avp', '.avs', '.avs', '.avv', '.axm', '.bdm', '.bdmv', '.bdt2', '.bdt3', '.bik', '.bin', '.bix',
'.bmk', '.bnp', '.box', '.bs4', '.bsf', '.bvr', '.byu', '.camproj', '.camrec', '.camv', '.ced', '.cel', …Run Code Online (Sandbox Code Playgroud) 这两种错误之间的差异是什么?什么时候使用它们?