小编use*_*899的帖子

我正在开发一个带有后台线程的Python应用程序,用于消费来自RabbitMQ队列的消息(主题场景).

我在Button的on_click事件上启动线程.这是我的代码,请注意"#self.receive_command()".

def on_click_start_call(self,widget):


    t_msg = threading.Thread(target=self.receive_command)
    t_msg.start()
    t_msg.join(0)
    #self.receive_command()


def receive_command(self):

    syslog.syslog("ENTERED")

    connection = pika.BlockingConnection(pika.ConnectionParameters(host='localhost'))
    syslog.syslog("1")

    channel = connection.channel()
    syslog.syslog("2")

    channel.exchange_declare(exchange='STORE_CMD', type='topic')
    syslog.syslog("3")

    result = channel.queue_declare(exclusive=True)
    syslog.syslog("4")

    queue_name = result.method.queue
    syslog.syslog("5")

    def callback_rabbit(ch,method,properties,body):
        syslog.syslog("RICEVUTO MSG: RKEY:"+method.routing_key+" MSG: "+body+"\n")

    syslog.syslog("6")

    channel.queue_bind(exchange='STORE_CMD', queue=queue_name , routing_key='test.routing.key')
    syslog.syslog("7")

    channel.basic_consume(callback_rabbit,queue=queue_name,no_ack=True)
    syslog.syslog("8")

    channel.start_consuming()

如果我运行此代码,我在syslog上看不到消息1,2,3,5,6,7,8但我只能看到"已输入".所以,代码被锁定在pika.BlokingConnection上.

如果我运行相同的代码(注释线程指令并取消对函数的直接调用),则所有代码都按预期工作并正确接收消息.

有任何解决方案可以将消费者运行到线程中吗？

提前致谢

达维德