小编isa*_*ess的帖子

最近在将调试器添加到我的python 2.7.10代码时,我得到以下消息:

Traceback (most recent call last):
  File "/Users/isaachess/Programming/vivint/Platform/MessageProcessing/vivint_cloud/queues/connectors/amqplib_connector.py", line 191, in acking_callback
    callback(message.body)
  File "/Users/isaachess/Programming/vivint/Platform/MessageProcessing/vivint_cloud/queues/consumable_message_queue.py", line 32, in deserialized_callback
    self._callback_method(msg)
  File "/Users/isaachess/Programming/vivint/Platform/BusinessLogic/businesslogic/util/statsd_util.py", line 95, in _time_func
    retVal = f(*args, **kwargs)
  File "/Users/isaachess/Programming/vivint/Platform/MessageProcessing/vivint_cloud/net/router.py", line 226, in handle
    try:
  File "/Users/isaachess/Programming/vivint/Platform/MessageProcessing/vivint_cloud/net/router.py", line 226, in handle
    try:
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/bdb.py", line 49, in trace_dispatch
    return self.dispatch_line(frame)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/bdb.py", line 68, in dispatch_line
    if self.quitting: raise BdbQuit
BdbQuit

这是在插入行之后:

import pdb; pdb.set_trace()

在代码中.

我无法弄清楚为什么会这样.我已经阅读了Bdb和Bdbquit,但无法弄清楚为什么会在我的代码中发生这种情况.任何人都可以向我提供一些为什么会发生这种情况的提示吗？我真的想让调试器再次运行.

我有一个简单的jsx问题,所以请原谅我的愚蠢.

我正在使用React的jsx命令行编译器.我有一个非常简单的JSX文件,如下所示:

var helloWorld = React.createClass({
    render: function() {
        return <div>hello</div>
    }
})

如果我在命令行中键入以下内容,它将编译(并在控制台中显示结果): jsx test.jsx

我想输出这个文件test.js.但是如果我尝试命令jsx test.jsx test.js没有任何反应 - 它只输出jsx命令的帮助信息.

有任何想法吗？我觉得它应该是显而易见的.