似乎我已经以某种方式git进入了一个不会提交的状态,因为已删除的文件不存在:
~/src$ git status -u # On branch master # Your branch is ahead of 'origin/master' by 5 commits. # (use "git push" to publish your local commits) # # Changes to be committed: # (use "git reset HEAD ..." to unstage) # # deleted: release-vars.sh # ~/src$ git commit -a fatal: pathspec 'release-vars.sh' did not match any files ~/src$ ls release-vars.sh ls: cannot access release-vars.sh: No such file or directory
关于如何解决这种情况的任何想法？
由于以下原因，我尝试配置 CMake 项目失败：
CMake Error at CMakeLists.txt:42 (install):
install FILES given directory
"/home/steve/udunits2/build/lib/udunits2lib.html" to install.
Call Stack (most recent call first):
lib/CMakeLists.txt:47 (texi_doc)
顶级 CMakeLists.txt 文件中的第 42 行是
install(FILES "${CMAKE_CURRENT_BINARY_DIR}/${file}.html" DESTINATION ${CMAKE_INSTALL_DOCDIR})
是从 .texi 输入构建 .info 和 .html 文件并安装它们的函数的一部分。${CMAKE_INSTALL_DOCDIR}是“共享/doc/udunits”。
此错误消息是什么意思以及如何解决该问题？
我使用 Gradle 而不是 Maven。如何让我们的 Jenkins 持续集成服务器不使用 Maven？我已经告诉 Jenkins 关于 Gradle，Jenkins 使用它来构建项目。然而，Jenkins 仍然坚持使用 Maven 重建项目，即使我已经从项目配置中删除了与 Maven 相关的所有内容。
命令vagrant up失败,我不知道为什么.
$ egrep -v '^ *(#|$)' Vagrantfile
VAGRANTFILE_API_VERSION = "2"
Vagrant.configure(VAGRANTFILE_API_VERSION) do |config|
config.vm.box = "precise32"
end
$ vagrant up
Bringing machine 'default' up with 'virtualbox' provider...
[default] Importing base box 'precise32'...
[default] Matching MAC address for NAT networking...
[default] Setting the name of the VM...
[default] Clearing any previously set forwarded ports...
[default] Creating shared folders metadata...
[default] Clearing any previously set network interfaces...
[default] Preparing network interfaces based on configuration...
[default] Forwarding ports...
[default] -- …以下用于简单哈希函数的代码无法编译
#include <cstddef>
#include <functional>
namespace {
struct Foo {
long i;
};
}
namespace std {
template<> struct hash<::Foo> {
size_t operator()(::Foo foo) const {
return hash<decltype(foo.i)>(foo.i);
}
};
}
我的4.8.5 g ++编译器发出以下消息：
$ g++ -std=c++11 a.cpp
a.cpp: In member function ‘std::size_t std::hash<{anonymous}::Foo>::operator()({anonymous}::Foo) const’:
a.cpp:13:47: error: no matching function for call to ‘std::hash<long int>::hash(long int&)’
return hash<decltype(foo.i)>(foo.i);
^
a.cpp:13:47: note: candidates are:
In file included from /usr/include/c++/4.8.2/bits/basic_string.h:3033:0,
from /usr/include/c++/4.8.2/string:52,
from /usr/include/c++/4.8.2/stdexcept:39,
from /usr/include/c++/4.8.2/array:38,
from /usr/include/c++/4.8.2/tuple:39,
from /usr/include/c++/4.8.2/functional:55,
from a.cpp:2: …让匿名本地函数对象访问包含方法的参数的正确方法是什么？即,执行以下操作的正确方法是什么:
void A::foo(B& b)
{
struct {
void operator()() {b.bar();}
} func;
func();
}
注意:这个例子是为了简单而设计的:实际的用例涉及将匿名本地函数对象应用于容器中的每个元素,以使元素作用于包含方法的参数.