我有一个字符串(tagList)列表需要在多个线程之间共享进行读取,所以我创建了一个不可修改的版本并将其传递给线程,我不确定它是否是线程安全的,因为线程只读取该列表所以我猜应该没问题?
当我将该不可修改的列表传递给线程时,它是否传递单个副本并由线程共享,还是创建多个副本并将一个副本传递给每个线程?
这是我的代码:
final List<String> tList = Collections.unmodifiableList(tagList);
List<Future<Void>> calls = new ArrayList<Future<Void>>();
FileStatus[] fsta = _fileSystem.listStatus(p);
for (FileStatus sta : fsta) {
final Path path = new Path(sta.getPath(), "data.txt");
if (!_fileSystem.exists(path)) {
continue;
}
else {
calls.add(_exec.submit(new Callable<Void>() {
@Override
public Void call() throws Exception {
filterData(path, tList);
return null;
}
}));
}
}
Run Code Online (Sandbox Code Playgroud) 我有类似的字符串"align is going to school sad may me"
.我想在四个空格后得到子字符串.字符串将在运行时输入.任何人都可以建议我在一些空格后找到Sub String ......
String st = "align is going to school sad may me";
int i = 0;
String [] strings = new String [15];
StringTokenizer stringTokenizer = new StringTokenizer (st, " ");
while (stringTokenizer.hasMoreElements ())
{
strings [i]= (String)stringTokenizer.nextElement ();
i++;
}
System.out.println ("I value is" + i);
for (int j=4; j<i; j++)
{
System.out.print (strings[j] + " ");
}
Run Code Online (Sandbox Code Playgroud)
我已经尝试了这个,它的工作可以请你建议我在一些空格后找到Sub字符串的简单方法.
在下面的程序中,使用时询问他想从哪个数字范围生成10个随机数,但是,一旦用户输入他的选择,打印的数字都是相同的?
import java.io.*;
public class RandomInt
{
public static void main (String [] args) throws IOException
{
String inGuess;
int theGuessInt = 0;
int theNum;
int theNum2;
BufferedReader myInput = new BufferedReader (new InputStreamReader (
System.in));
System.out
.println ("Hello this program generates random numbers from 0-10 or 20-30");
System.out
.println ("Please input '1' for the random generation of 0-10, or '2' for the generation of 20-30");
inGuess = myInput.readLine ();
theGuessInt = Integer.parseInt (inGuess);
// Generate random numbers from 0 …
Run Code Online (Sandbox Code Playgroud)