小编Cha*_*ick的帖子

这是我的表1:

Name        Description  
john        student       
dom         teacher

我需要使用SELECT * INTO到它转移到另一个表(table2),但我有一个名为新列希望它Auto是自动递增.

这将是这样的:

Name       Description        Auto
John        Student            1
Dom         Teacher            2

现行代码: SELECT * INTO table2 FROM table1

我刚刚从我的项目中创建了一个C++问题,我编译了程序并给了我一个错误,但是给了我一个警告,我无法运行或测试程序.

#include <iostreamn.h>
#include <conio.h>
#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main()
{
    int grossincome,totaldeduction,tax,output;

    cout<<"Input gross income: "<<endl;
    cin>>grossincome;
    cout<<"Input total deductions: "<<endl;
    cin>>totaldeduction;

    if (grossincome > 100000)
    {
       tax = (grossincome * .20);
       output = (grossincome - totaldeduction - tax);
    }
    else if((grossincome <= 100000) && (grossincome >= 50000))
    {
       tax = (grossincome * .15);
       output = (grossincome - totaldeduction - tax);
    }
    else if(grossincome < 50000)
    {
       tax = (grossincome * .10);
       output = (grossincome - …

我有一张tblEmployeeInfo至少有100+ 的桌子column name.我想知道那张column name桌子里有多少人.那可能吗？

注意: tbleEmployeeInfo还没有数据.