小编KAK*_*KAK的帖子

do{        
            float diameter;

            scanf("%f",&diameter);  
            Printf("Please input diameter");
            if(cheack1(diameter) == 0){
                Printf("Please input a valid number greater than 0");
            }else{
                circle(&area, &perimeter, diameter);
            }

            int cheack = cheack1(diameter);
}while(cheack == 1);

我的do-while循环有问题.如你所见,我已经宣布了

int cheack = cheack1(diameter); 在cheack1(diameter);cheacks如果我输入的是正确的,如果它是正确的返回1.

但我的错误是:

p7t5.c: In function ‘main’: p7t5.c:87:11: error: ‘cheack’ undeclared (first use in this function) 似乎while(cheack == 1);是不记得cheackdo-while循环内部.

我正在尝试打印一个数组但是我没有得到所需的输出,在循环完成打印预定义数组后会出现奇怪的数字.

代码是:

#include <stdio.h>    
int main(){    
    int intArray[11] = {1,2,8,12,-13,-15,20,99,32767,10,31};
    int i=0;        
    for(i=0;i<sizeof(intArray);i++){
        printf("%d\n",intArray[i]);
    }
}

输出:

1
2
8
12
-13
-15
20
99
32767
10
31
11
1629976468
2674040
2665720
1627423265
1
2665616
-2147417856
1629976534
1629976468
2674040
0
1627423172
1629976532
0
1629110043
0
0
0
0
0
0
0
0
0
0
0
1629976538
0
1629956432
2674276
0
1627407935

我知道这可能是一个简单的错误,但我仍然无法弄清楚错误.我正进入(状态

当我打印出整数时,指针地址而不是值.

#include<stdio.h>

int main(){

    char s1[100];

    int words,lines,chara = 0;


    FILE * fp;

    fp  = fopen("fox.txt","r");

    if(fp==NULL){
        printf("Can't open file");
    }
    else{
        while (fscanf(fp,"%s",s1) != EOF){

            words++;

        //  printf("%s",s1);
            }

    }
        printf("There are %d of words",words);
}

fox.txt

The quick 

brown fox
jumps over

the lazy 


dog

输出:

There are 2665625 of words

private int[] list = {1,2,3,4,5,6,7,8,9};

我应该用什么代码从这个列表中随机获取但唯一的数字.请为我提供最简单的初学者方式.谢谢你的帮助.