虽然是一个简单的问题,但我已经搜索了几天没有成功。
M = My machine
J = Jump Host
S = Server
Jump Host has my public key on authorized_keys.
Server has J's public key on authorized_keys.
Allowed connections (due to key authentication):
M -> J
J -> S
Run Code Online (Sandbox Code Playgroud)
我怎么可能从我的机器 ssh 进入 S?
我目前的配置是:
host jump
user root
HostName x.x.x.x
host server
user root
HostName x.x.x.x
port 22
ForwardAgent no
ProxyCommand ssh jump -W %h:%p
Run Code Online (Sandbox Code Playgroud)
当它尝试使用 M 的密钥登录时它不起作用。
这是 ssh 日志
debug1: Host 'x.x.x.x' is known and matches the ECDSA …Run Code Online (Sandbox Code Playgroud) 我一直在收到Uncaught ReferenceError: $ is not defined错误.我认为一切都很好并且正常工作.我的JQuery代码在我的Javascript文件中.我认为这不是它的工作原理吗?我应该有一个JQuery文件吗?
我把它放在我的HTML头脑中
<script src="http://ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script>
这是我的Javascript文件:
function typing(id, sentence){
var result = $.Deferred();
var index=0;
var intObject= setInterval(function() {
document.getElementById(id).innerHTML+=sentence[index];
index++;
if(index==sentence.length){
clearInterval(intObject);
}
}, 100);
return result.promise();
}
var sleep = function(ms) {
var result = $.Deferred();
setTimeout(result.resolve, ms);
return result.promise();
};
typing('container','Subject Name:').then(function() {
return sleep(500);
}).then(function() {
return typing('container',' Carlos Miguel Fernando')
});
Run Code Online (Sandbox Code Playgroud)
我哪里做错了?
我正在编写一个简单的命令行游戏.我有很多功能,而且只会发布必要的功能.
问题:程序编译但是当levelup()调用并且选择了一个数字时,我得到了这个:
You have 5 skill points to spend.
What would you like to upgrade?
[1:] STR [2:] DEF
1
Exception in thread "main" java.lang.NullPointerException
at Game.levelup(cmdquest.java:300)
at Game.start(cmdquest.java:336)
at Menu.show_menu(cmdquest.java:195)
at cmdquest.main(cmdquest.java:263)
Run Code Online (Sandbox Code Playgroud)
这是我的代码:
class Player{
String name;
int hp;
int str;
int def;
String eff;
Player(String n) {
name = n;
hp = 100;
str = 1;
def = 1;
eff = "none";
}
}
class Game{
static Player p;
static void levelup(){
while (points > 0){ …Run Code Online (Sandbox Code Playgroud)