小编use*_*271的帖子

将C#转换为VB.Net时,未声明"InlineAssignHelper"

这是我在C#中的代码:

 ListBox l = new ListBox();
        foreach (string[] s in Regex.Matches(new WebClient().DownloadString("http://www.hidemyass.com/proxy-list/search-229092"), @"(?:<td class=""leftborder timestamp""(?s).+?<style>)((?s).+?)\s*<td>\s+(\d{2,5})</td>").Cast<Match>().Select(m => new string[] { m.Groups[1].Value, m.Groups[2].Value }))
        {
            Regex.Matches(s[0], @"\.([^\{]+)\{([^\}]+)\}").Cast<Match>().ToList().ForEach(m => s[0] = s[0].Replace(string.Format(@"class=""{0}""", m.Groups[1].Value), string.Format(@"style=""{0}""", m.Groups[2].Value)));
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现在这里是什么码出来后,我把它转换使用:

     Dim l As New ListBox()
    For Each s As String() In Regex.Matches(New WebClient().DownloadString("http://www.hidemyass.com/proxy-list/search-229092"), "(?:<td class=""leftborder timestamp""(?s).+?<style>)((?s).+?)\s*<td>\s+(\d{2,5})</td>").Cast(Of Match)().[Select](Function(m) New String() {m.Groups(1).Value, m.Groups(2).Value})
        Regex.Matches(s(0), "\.([^\{]+)\{([^\}]+)\}").Cast(Of Match)().ToList().ForEach(Function(m) InlineAssignHelper(s(0), s(0).Replace(String.Format("class=""{0}""", m.Groups(1).Value), String.Format("style=""{0}""", m.Groups(2).Value))))
        l.Items.Add(String.Concat(Regex.Matches(Regex.Replace(Regex.Replace(s(0), "<(span|div) style=""display:none"">[\d\.]+</\1>", String.Empty).Remove(0, s(0).IndexOf("/style>")), "class=""\d+""", String.Empty), "[\d\.]+").Cast(Of Match)().[Select](Function(m) m.Value)) & ":" & s(1))
    Next
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我收到一个错误说: …

c# vb.net converter

18
推荐指数
1
解决办法
1万
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