我一直相信你继续使用如下:
var i;
for (i = 0; i < 10; i++) {
if(i%2===0) {
continue;
}
}
要么
var i, myloop;
myloop: for (i = 0; i < 10; i++) {
if(i%2===0) {
continue myloop;
}
}
但是当我通过JSLint运行这两段代码时,我得到错误:
Problem at line 5 character 5: Unexpected 'continue'.
continue;
我究竟做错了什么？什么是正确的用法？
我正在尝试使用MethodInfo MakeGenericMethod,如下所示:
foreach (var type in types)
{
object output = null;
var method = typeof (ContentTypeResolver).GetMethod("TryConstruct");
var genmethod = method.MakeGenericMethod(type);
var arr = new object[] { from, output };
if ((bool)genmethod.Invoke(null, arr))
return (IThingy)arr[1];
}
针对以下通用方法:
public static bool TryConstruct<T>(string from, out IThingy result) where T : IThingy, new()
{
var thing = new T();
return thingTryConstructFrom(from, out result);
}
我遇到的问题是我在MakeGenericMethod行上得到了一个争论异常,因为我传递的类型不是'new()'
这有什么办法？谢谢
我正在向请求对象添加一个cookie,并从响应中的当前时间中减去它,但我假设有更好的方法来执行此操作.此外,重新使用相同的Cookie密钥可能在实际用例中不起作用.
有任何想法吗？
RequestFilters.Add((request, response, dto) =>
{
request.Cookies.Add("Start", new Cookie("Start", DateTime.Now.ToString()));
request.ResponseContentType = ContentType.Json;
});
ResponseFilters.Add((request, response, dto) =>
{
Console.WriteLine("{0} : [{1}]", request.RawUrl, DateTime.Now.Subtract(DateTime.Parse(request.Cookies["Start"].Value)).Milliseconds);
request.Cookies.Clear();
});
我一直在努力.
我怎么写这个:
/* initialization */ List<Tuple<string, string, string>> mytuple = new List<Tuple<string, string, string>>();
//pseudocode
if(mytuple.Contains("hello") in Item2)
{
Console.Write("Success");
}
我有以下jQuery,点击按钮切换手风琴菜单:
jQuery的:
$(function() {
$('#chooseOption').click(function(){
$('#accordion ul').toggle();
});
});
它很棒!
现在,我想知道我是否可以在切换时更改CSS height和background元素.所以,当我点击chooseOption它会改变height与background该元素的.
默认CSS:
#chooseOption {height:35px;background-image:url('1.jpg');}
单击它将更改为:
#chooseOption {height:55px;background-image:url('2.jpg');}
非常感谢您对此的任何指示.
假设我的几个控制器构造函数采用接口 - IPetInterface IPetInterface有3个具体实现.
您将如何配置StructureMap以基于需要它的控制器提供其中一个具体实现.
原油的例子....
class DogStuff: IPetInterface{}
class CatStuff: IPetInterface{}
class GiraffeStuff: IPetInterface{}
class DogController : Controller
{
DogController(IPetInterface petStuff)
// some other stuff that is very unique to dogs
}
class CatController : Controller
{
CatController(IPetInterface petStuff)
// some other stuff that is very unquie to cats
}
我正在尝试用泛型编写简单的C#函数.例如,数组解析器.
public static int parse_array <T> ( string str, ref T[] array )
where T : IConvertible<T>
{
string[] vals=str.Split(new char[]{'','\t',',',';'}, StringSplitOptions.RemoveEmptyEntries);
if( vals==null || vals.Length==0 )
return 0;
array = new T[vals.Length];
for( int i=0; i<vals.Length; i++ )
{
array[i] = Convert.ChangeType ( vals[i], T );
}
return vals.Length;
}
但我收到错误:非泛型类型'System.IConvertable'不能与type参数一起使用.怎么了 ？
我有我的域名字符串:
www.my.domain.com
我希望我的输出是:
my.domain
我现在这样做:
str.replace("www.","").replace(".com","")
如何只用一个替换而不是两个？
我是Sencha Extjs的新手,我遇到了模型设计问题.以下是来自服务器的示例响应:
[
{
"success": "true",
"data": {
"sromain": [
{
"corporation": "DEV 1 s.r.o.",
"dbName": "dev_1_s_r_o_",
"prijmyCelk": "2 106,00 €",
"nakladyCelk": "2 049,00 €",
"ziskCelk": "57,00 €",
"neuhrVydCelk": "2 106,00 €",
"neuhrPrijCelk": "2 049,00 €",
"dph": "9,52 €"
}
],
"branches": [
{
"branch_name": "Bratislava",
"branch_code": "BA",
"strediskoprijmyCelk": "180,00 €",
"strediskonakladyCelk": "0,00 €",
"strediskoziskCelk": "180,00 €",
"strediskoneuhrVydCelk": "180,00 €",
"strediskoneuhrPrijCelk": "0,00 €",
"streddphCelk": "30,00 €"
},
{
"branch_name": "Banská Bystrica",
"branch_code": "BB",
"strediskoprijmyCelk": "600,00 €",
"strediskonakladyCelk": "0,00 €",
"strediskoziskCelk": …我如何在多个表中搜索？我有这个代码,但这只适用于我的一个表.我总共有4张桌子.
这是我的表格中"某事"之后的搜索代码.
$(document).ready(function() {
$('#search').keyup(function() {
searchTable($(this).val());
});
});
function searchTable(inputVal) {
var table = $('#searchTable');
table.find('tr').each(function(index, row) {
var allCells = $(row).find('td');
if(allCells.length > 0) {
var found = false;
allCells.each(function(index, td) {
var regExp = new RegExp(inputVal, 'i');
if(regExp.test($(td).text())) {
found = true;
return false;
}
});
if(found == true) $(row).show();
else $(row).hide();
}
});
}
我已经剥离了我的表格代码,以便它看起来更易于管理
问题在于"搜索tabe"只运行表1而不是剩余的表
表格1:
<table class="table" id="searchTable">
表2:
<table class="table" id="searchTable">
表3:
<table class="table" id="searchTable">
表4:
<table class="table" id="searchTable">
我试图在javascript中为元素(id ctl30_txtTextBox)设置一个值.
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "IndexMask.aspx/AttachBarcodeFile",
dataType: "json",
data: params,
success: function() {
$("#<%= DummyPostbackButton.ClientID %>").click();
var someOtherName = "abc";
var element = document.getElementById("ctl30_txtTextBox");
element.Value = someOtherName;
alert(element.value.toString());
},
error: function(request, status, error) {
alert("Error attaching barcode file.");
}
});
我得到了元素,但价值从未设定.如果我在页面上设置了值,则会显示具有正确值的警报.
我究竟做错了什么？