小编Mat*_*ell的帖子

如何从SQL数据库查询中随机选择一行？我的意思是:

从table1中选择所有类别为"green"的东西:

$stmt = $db->query('SELECT * from table1 WHERE Category LIKE "%green%"');

然后从该选择中随机显示一行(而不是显示此选择中的每一行,如下所示)

while($rows = $stmt->fetch()){
     echo "<tr><td>". $rows['Number'] . "</td><td>" . $rows['Content'] . "</td></tr>";
};

在我的页面中,我有不同的菜单项,可以触发不同的相应图片.将z-index相应的图片切换到顶部.这是代码:

$(document).ready(function(){

var doorOpen = false;

$("a[href=#andrew]").click(function() {

    if (doorOpen) { // set animation duration for door close, based on actually needed to animate the door closed or not
        var duration = 1500;
    } else {
        var duration = 0;
    }

    $("#rightdoor,#leftdoor").animate(
        {"marginLeft":"0px"},
        {duration:duration,
            complete:function() {
                $('.pic2 .pic3 .pic4 .pic5').css('zIndex', 1);  //puts wrong pics in back
                $('.pic1').css('zIndex', 2);  //brings right pic into view
                $('#rightdoor').animate({  //opens doors again
                 marginLeft: "150px",
                }, 1500);
                $('#leftdoor').animate({
                 marginLeft: "-150px",
                }, 1500);
            }
        } …